Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water. Y is often called isopropyl alcohol and it is a component in many personal care products. Y can also be produced by the reduction of compound Z. $$\text{CH}_3\text{CH}_2\text{CH}_2 \rightarrow \text{H}_2\text{O} \rightarrow \text{CH}_3\text{CH(OH)CH}_3$$ A hand sanitizer with a high concentration of an alcohol are effective in destroying most bacteria and viruses on the skin. The ability of alcohols to form strong hydrogen bonds is involved in the mechanism of disrupting bacteria and virus protein. (i) A hand sanitizer labelled 70% (v/v) isopropyl alcohol contains only water and Y. Express its concentration in terms of moles per litre of isopropyl alcohol. Take the density of isopropyl alcohol as 0.8 g cm⁻³.

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Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water - Leaving Cert Chemistry - Question 8 - 2021

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Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water. Y is often called isopropyl alcohol and it is a component i... show full transcript

Worked Solution & Example Answer:Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water - Leaving Cert Chemistry - Question 8 - 2021

Step 1

Express its concentration in terms of moles per litre of isopropyl alcohol.

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Answer

To find the concentration in moles per litre, follow these steps:

Calculate the volume of isopropyl alcohol in 100 cm³: The sanitizer is 70% (v/v), hence:

$70 \text{ cm}^3 \text{ CH}_3\text{CH(OH)CH}_3 \text{ per } 100 \text{ cm}^3$
Calculate the volume of isopropyl alcohol in 1 litre:

$700 \text{ cm}^3 \text{ CH}_3\text{CH(OH)CH}_3 \text{ per litre}$
Calculate the mass of isopropyl alcohol: Using density (0.8 g/cm³):

$700 \text{ cm}^3 \times 0.8 \text{ g/cm}^3 = 560 \text{ g CH}_3\text{CH(OH)CH}_3 \text{ per litre}$
Calculate the number of moles of isopropyl alcohol: The molar mass of isopropyl alcohol (C₃H₈O) is approximately 60.094 g/mol. Thus:

$n = \frac{\text{mass}}{\text{molar mass}} = \frac{560 \text{ g}}{60.094 \text{ g/mol}} \approx 9.3 \text{ moles per litre}$

Thus, the concentration of isopropyl alcohol is approximately 9.33 moles per litre.

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Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water - Leaving Cert Chemistry - Question 8 - 2021

Worked Solution & Example Answer:Study the reaction scheme below in which compound Y is produced by the reaction of compound X with water - Leaving Cert Chemistry - Question 8 - 2021

Express its concentration in terms of moles per litre of isopropyl alcohol.

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