The external wall of a house built in the 1990s is of 100 mm concrete block construction with a 100 mm partially filled cavity, as shown - Leaving Cert Construction Studies - Question 5 - 2019
Question 5
The external wall of a house built in the 1990s is of 100 mm concrete block construction with a 100 mm partially filled cavity, as shown.
(a) Calculate the U-value ... show full transcript
Worked Solution & Example Answer:The external wall of a house built in the 1990s is of 100 mm concrete block construction with a 100 mm partially filled cavity, as shown - Leaving Cert Construction Studies - Question 5 - 2019
Step 1
Calculate the U-value of the wall
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Answer
To calculate the U-value of the wall, we first need to find the total resistance (R) of each layer and then apply the formula for U-value.
Resistance Calculation:
External Render:
Thickness = 0.016 m,
Resistivity = 0.048 m² °C/W.
Concrete Block Outer Leaf:
Thickness = 0.1 m,
Conductivity = 1.440 W/m °C.
Clear Cavity:
Resistance = 0.170 m² °C/W.
Polystyrene Insulation:
Thickness = 0.1 m,
Conductivity = 0.037 W/m °C.
Concrete Block Inner Leaf:
Thickness = 0.1 m,
Conductivity = 1.440 W/m °C.
Internal Plaster:
Thickness = 0.012 m,
Conductivity = 6.250 W/m °C.
Internal Surface Resistance:
R = 0.012 m² °C/W.
Total Resistance Calculation:
Using the resistances:
Rtotal=Rexternal+Router+Rcavity+Rinsulation+Rinner+Rplaster+Rinternal
To find U-value:
U=Rtotal1
Calculating this gives us:
Rtotal=0.048+0.069+0.170+2.703+0.069+0.005+0.012
Conclusively, calculating yields:
U=0.516m2°CW
Step 2
Using the U-value obtained at 5(a) calculate cost of heat loss
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Answer
The heat loss through the wall can be calculated using:
Heat Loss Formula:
Heat loss=U×Area×Temp. diff.
Given Values:
U-value = 0.516 W/m²°C
Area = 135 m²
Temperature difference = (19 - 5) °C = 14 °C
Calculation:
Heat loss per second:
Heat loss=0.516×135×14
This results in:
975.24Watts
Heat input in heating hours:
Total heating period = 60 hours × 36 weeks = 2168 hours.
Total heat loss condenses to:
Total Loss=975.24×2168
Divide by 1000 to convert to kW:
1000Total Loss
Cost Calculation with caloric values gives:
Therefore:
Cost=212.34×0.94
Final Cost Affiliation leads to about £199.60 annually.
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