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It is proposed to replace the single glazing in a dwelling house with double glazing - Leaving Cert Construction Studies - Question 5 - 2008

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It is proposed to replace the single glazing in a dwelling house with double glazing. (a) Using the following data, calculate the U-value of the: (i) single glazin... show full transcript

Worked Solution & Example Answer:It is proposed to replace the single glazing in a dwelling house with double glazing - Leaving Cert Construction Studies - Question 5 - 2008

Step 1

Using the following data, calculate the U-value of the: (i) single glazing

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Answer

To calculate the U-value for single glazing:

  1. Total Resistance (R): Using the formula:

    R=Rinternal+Rglass+RexternalR = R_{internal} + R_{glass} + R_{external}

    Where:

    • Resistance of internal surface = 0.122 m²°C/W
    • Resistance of glass = ( R_{glass} = \frac{T}{k} = \frac{0.005}{1.02} = 0.0049 m²°C/W )
    • Resistance of external surface = 0.080 m²°C/W

    Thus,

    R=0.0049+0.122+0.080=0.2069m2°C/WR = 0.0049 + 0.122 + 0.080 = 0.2069 m²°C/W

  2. U-value Calculation:

    Using the formula:

    U=1RU = \frac{1}{R}

    Therefore,

    U=10.20694.83W/m2°CU = \frac{1}{0.2069} \approx 4.83 W/m²°C

Step 2

Using the following data, calculate the U-value of the: (ii) standard double glazing

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Answer

To calculate the U-value for standard double glazing:

  1. Total Resistance (R): Using the formula:

    R=Rinternal+Rglass1+Rspace+Rglass2+RexternalR = R_{internal} + R_{glass1} + R_{space} + R_{glass2} + R_{external}

    Where:

    • Resistance of glass = ( R_{glass1} = \frac{4 \times 0.004}{1.02} = 0.0784 m²°C/W )
    • Resistance of space = 0.170 m²°C/W
    • Resistance of second glass (same as first) = 0.0784 m²°C/W

    Thus,

    R=0.122+0.0784+0.170+0.0784+0.080=0.5m2°C/WR = 0.122 + 0.0784 + 0.170 + 0.0784 + 0.080 = 0.5 m²°C/W

  2. U-value Calculation:

    Thus,

    U=10.5=2.00W/m2°CU = \frac{1}{0.5} = 2.00 W/m²°C

Step 3

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: - single glazing

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Answer

For single glazing:

  1. Heat Loss Calculation:

    Using the formula:

    HeatLoss=U×Area×TemperatureDifferenceHeatLoss = U \times Area \times Temperature\,Difference

    Where:

    • U-value = 4.83 W/m²°C
    • Area = 25 m²
    • Temperature difference = 18 °C - 5 °C = 13 °C

    Thus,

    HeatLoss=4.83×25×13=1569.75WHeat Loss = 4.83 \times 25 \times 13 = 1569.75 W

  2. Annual Heat Loss:

    To find annual heat loss in kJ:

    AnnualHeatLoss=1569.75×60×60×11×40=17403588 kJAnnualHeatLoss = 1569.75 \times 60 \times 60 \times 11 \times 40 = 17403588 \text{ kJ}

  3. Cost Calculation:

    Using the calorific value of oil:

    AnnualCost=1740358837350×0.80=372.80AnnualCost = \frac{17403588}{37350} \times 0.80 = €372.80

Step 4

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: - double-glazed

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Answer

For double glazing:

  1. Heat Loss Calculation:

    Using the U-value of double glazing:

    U=2.63W/m2°CU = 2.63 W/m²°C

    Thus,

    HeatLoss=2.63×25×13=854.75WHeat Loss = 2.63 \times 25 \times 13 = 854.75 W

  2. Annual Heat Loss:

    To find annual heat loss in kJ:

    AnnualHeatLoss=854.75×60×60×11×40=9477468 kJAnnualHeatLoss = 854.75 \times 60 \times 60 \times 11 \times 40 = 9477468 \text{ kJ}

  3. Cost Calculation:

    Using the calorific value of oil:

    AnnualCost=947746837350×0.80=202.99AnnualCost = \frac{9477468}{37350} \times 0.80 = €202.99

Step 5

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: - low-e double glazing

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Answer

For low-e double glazing:

  1. Heat Loss Calculation:

    Using the U-value of low-e double glazing:

    U=1.1W/m2°CU = 1.1 W/m²°C

    Thus,

    HeatLoss=1.1×25×13=357.5WHeat Loss = 1.1 \times 25 \times 13 = 357.5 W

  2. Annual Heat Loss:

    To find annual heat loss in kJ:

    AnnualHeatLoss=357.5×60×60×11×40=3963960 kJAnnualHeatLoss = 357.5 \times 60 \times 60 \times 11 \times 40 = 3963960 \text{ kJ}

  3. Cost Calculation:

    Using the calorific value of oil:

    AnnualCost=396396037350×0.80=84.90AnnualCost = \frac{3963960}{37350} \times 0.80 = €84.90

Step 6

Using the information obtained at (b) above, recommend a preferred glazing type and give two reasons to support your recommendation.

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Answer

Based on the costs calculated:

  1. Recommendation: The preferred glazing type is low-e double glazing.

  2. Reasons for Recommendation:

    • The annual heating cost for low-e double glazing (€84.90) is significantly lower than that for both single (€372.80) and standard double glazing (€202.99).
    • Low-e double glazing is four to five times more efficient compared to single glazing, thus providing better thermal insulation and comfort.

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