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It is proposed to replace the single glazing in a dwelling house with double glazing - Leaving Cert Construction Studies - Question 5 - 2008

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It is proposed to replace the single glazing in a dwelling house with double glazing. (a) Using the following data, calculate the U-value of the: (i) single glazing... show full transcript

Worked Solution & Example Answer:It is proposed to replace the single glazing in a dwelling house with double glazing - Leaving Cert Construction Studies - Question 5 - 2008

Step 1

Using the following data, calculate the U-value of the: (i) single glazing.

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Answer

To calculate the U-value of single glazing, first, we find the total resistance (R) using the formula:
R=Rinternal+Rglass+RexternalR = R_{internal} + R_{glass} + R_{external}
The resistance of the single glazing (5 mm thick) is calculated as follows:

  • Resistance of the internal surface: Rinternal=0.122 m2°C/WR_{internal} = 0.122 \ m^2\degree{C}/W
  • Resistance of the glass: Rglass=Tk=0.0051.02=0.0049 m2°C/WR_{glass} = \frac{T}{k} = \frac{0.005}{1.02} = 0.0049 \ m^2\degree{C}/W
  • Resistance of the external surface: Rexternal=0.080 m2°C/WR_{external} = 0.080 \ m^2\degree{C}/W
    Therefore,
    RSingleGlazing=0.122+0.0049+0.080=0.2069 m2°C/WR_{SingleGlazing} = 0.122 + 0.0049 + 0.080 = 0.2069 \ m^2\degree{C}/W
    The U-value is given by the formula:
    U=1RU = \frac{1}{R}
    Calculating the U-value: USingleGlazing=10.20694.83 W/m2°CU_{SingleGlazing} = \frac{1}{0.2069} \approx 4.83 \ W/m^2\degree{C}

Step 2

Using the following data, calculate the U-value of the: (ii) standard double glazing.

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Answer

To calculate the U-value of standard double glazing, we first need to determine the overall resistance using the same method:

  • Resistance of the internal surface: Rinternal=0.122 m2°C/WR_{internal} = 0.122 \ m^2\degree{C}/W
  • Resistance of glass: Rglass=0.0041.020.0007843 m2°C/WR_{glass} = \frac{0.004}{1.02} \approx 0.0007843 \ m^2\degree{C}/W
  • Resistance of space between panes: Rspace=0.0120.1700.0706 m2°C/WR_{space} = \frac{0.012}{0.170} \approx 0.0706 \ m^2\degree{C}/W
  • Resistance of the external surface: Rexternal=0.080 m2°C/WR_{external} = 0.080 \ m^2\degree{C}/W
    Calculating total resistance: RDoubleGlazing=Rinternal+Rglass1+Rspace+Rglass2+RexternalR_{DoubleGlazing} = R_{internal} + R_{glass1} + R_{space} + R_{glass2} + R_{external}
    Thus, RDoubleGlazing=0.122+0.0007843+0.0706+0.0007843+0.080=0.2741 m2°C/WR_{DoubleGlazing} = 0.122 + 0.0007843 + 0.0706 + 0.0007843 + 0.080 = 0.2741 \ m^2\degree{C}/W
    Calculating the U-value: UDoubleGlazing=10.27413.65 W/m2°CU_{DoubleGlazing} = \frac{1}{0.2741} \approx 3.65 \ W/m^2\degree{C}

Step 3

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: (i) single glazing.

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Answer

Given the U-value of single glazing, the heat loss can be calculated using
HeatLoss=U×Area×Temp.DiffHeat \\ Loss = U \times Area \times Temp. \\ Diff
Where:

  • U-value of single glazing: 4.83W/m2°C4.83 W/m^2\degree{C}
  • Area: 25m225 m^2
  • Temperature difference: 185=13°C18 - 5 = 13\degree{C}
    Substituting values: HeatLoss=4.83×25×13=1569.75WattsHeat \\ Loss = 4.83 \times 25 \times 13 = 1569.75 \text{Watts}
    To find the annual heat loss, convert it: AnnualEnergy=60×60×11×7×40×1569.75=17403588 kJ per annumAnnual \\ Energy = 60 \times 60 \times 11 \times 7 \times 40 \times 1569.75 = 17403588 \text{ kJ per annum}
    Calculating cost per annum with the oil cost (80 cents per litre): Costperannum=1740358837350×0.80=372.80Cost per annum = \frac{17403588}{37350} \times 0.80 = €372.80

Step 4

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: (ii) double glazed.

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Answer

For double glazing use:

  • U-value: 2.63W/m2°C2.63 W/m^2\degree{C}
    Calculating heat loss: HeatLoss=2.63×25×13=854.75WattsHeat \\ Loss = 2.63 \times 25 \times 13 = 854.75 \text{Watts} Annual energy lost: AnnualEnergy=60×60×11×7×854.75=9477468kJperannumAnnual \\ Energy = 60 \times 60 \times 11 \times 7 \times 854.75 = 9477468 kJ \\ per annum Calculating cost per annum: Costperannum=947746837350×0.80=202.99Cost per annum = \frac{9477468}{37350} \times 0.80 = €202.99

Step 5

Using the U-values obtained at (a) above and the following data, calculate the cost of the heat lost annually through each of the following: (iii) low-e double glazed.

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Answer

For low-e double glazing, use:

  • U-value: 1.1W/m2°C1.1 W/m^2\degree{C}
    Calculating heat loss: HeatLoss=1.1×25×13=357.5WattsHeat \\ Loss = 1.1 \times 25 \times 13 = 357.5 \text{Watts}
    Annual energy lost: AnnualEnergy=60×60×11×7×357.5=3963960kJperannumAnnual \\ Energy = 60 \times 60 \times 11 \times 7 \times 357.5 = 3963960 kJ \\ per annum
    Calculating cost per annum: Costperannum=396396037350×0.80=84.90Cost per annum = \frac{3963960}{37350} \times 0.80 = €84.90

Step 6

Using the information obtained in (a) above, recommend a preferred glazing type and give two reasons to support your recommendation.

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Answer

Based on the calculations:

  • The single glazing incurs the highest cost of €372.80 annually.
  • The double glazing is more economical at €202.99 per year.
  • The low-e double glazing offers the best efficiency with a cost of only €84.90 annually. Thus, the recommended glazing type is low-e double glazing because:
  1. It results in significantly reduced heating costs compared to both single and standard double glazing.
  2. It enhances energy efficiency and offers better insulation, which can lead to long-term savings on energy bills.

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