A cam mechanism is a profiled shape (similar to the one shown on the right) mounted on a shaft that is used to convert rotary motion into linear motion - Leaving Cert DCG - Question C-4 - 2022
Question C-4
A cam mechanism is a profiled shape (similar to the one shown on the right) mounted on a shaft that is used to convert rotary motion into linear motion.
Draw the di... show full transcript
Worked Solution & Example Answer:A cam mechanism is a profiled shape (similar to the one shown on the right) mounted on a shaft that is used to convert rotary motion into linear motion - Leaving Cert DCG - Question C-4 - 2022
Step 1
0° to 90° Rise 70mm with Uniform Velocity
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To start the displacement diagram, plot the first segment for the range 0° to 90°. The follower rises 70mm with uniform velocity. This should be represented as a straight line rising to the 70mm mark.
Step 2
90° to 120° Dwell
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
For the interval from 90° to 120°, the follower remains at the 70mm height without any movement. This should be depicted as a horizontal line at the 70mm mark until the 120° point.
Step 3
120° to 180° Fall 20mm with Uniform Velocity
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
During the segment from 120° to 180°, the follower falls 20mm uniformly. This will appear as a straight line descending from the 70mm line to the 50mm line, ending at the mark corresponding to 180°.
Step 4
180° to 360° Fall 50mm with Simple Harmonic Motion
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
In this interval, the follower falls further down 50mm with simple harmonic motion. The graph should show a curve, starting at the 50mm mark at 180° and reaching the 0mm mark at 360°. The curvature can be approximated to represent the characteristics of simple harmonic motion.
Step 5
Draw Cylinder's Plan and Elevation
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Begin by drawing a rectangle to represent the elevation of the cylinder, with dimensions that correspond to its height of 120 mm. The plan view can be depicted as a circle drawn to scale, representing the top face of the cylinder.
Step 6
Complete Projections from Plan of Helix
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
From the plan view, mark a point representing the start of the helix and project lines upward to indicate the height of the helix. As you progress along the helix, ensure to maintain uniform spacing to reflect the regularity of the helical path.
Step 7
Locate Points in Elevation
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
In the elevation view, make sure to mark the ends of the helix on the cylinder’s side accurately. Use the projections to define the points along the height and curve of the helix.
Step 8
Draw Helix in Elevation
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Between points A and B, sketch the helix in elevation. Ensure it wraps around in an anticlockwise direction as it ascends from the base point A to the top point B.
Join the Leaving Cert students using SimpleStudy...