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The 3D graphic shows a trophy which is to be awarded to the best student in a DGC class - Leaving Cert DCG - Question B-2 - 2009

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Question B-2

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The 3D graphic shows a trophy which is to be awarded to the best student in a DGC class. The trophy consists of two interlocking coloured glass set squares. (The ma... show full transcript

Worked Solution & Example Answer:The 3D graphic shows a trophy which is to be awarded to the best student in a DGC class - Leaving Cert DCG - Question B-2 - 2009

Step 1

Draw the plan and elevation of the intersecting planes.

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Answer

  1. Start by plotting the points A, B, and C based on their coordinates:

    • Point A (145, 80, 30)
    • Point B (266, 80, 30)
    • Point C (170, 80, 75)
  2. Connect points A, B, and C to form triangle ABC.

  3. Similarly, plot points D, E, and F:

    • Point D (250, 90, 30)
    • Point E (145, 90, 30)
    • Point F (250, 90, 75)
  4. Connect points D, E, and F to create triangle DEF.

  5. Now, project the positions of triangles ABC and DEF to create a plan view and an elevation view on the same drawing.

Ensure appropriate line types are used for hidden and visible edges.

Step 2

Determine the line of intersection between the planes.

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Answer

To find the intersection line of the planes formed by triangles ABC and DEF:

  1. Identify the line segments of both triangles that intersect.

  2. Use vector equations to determine the intersection points. For example, using the coordinates of points A and D, and checking their directional vectors.

  3. The line of intersection lies along the coordinates that satisfy both plane equations at the points where triangle edges intersect.

Step 3

Determine the dihedral angle between the planes.

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Answer

The dihedral angle between two planes can be found using the normal vectors:

  1. Determine the normal vectors of triangles ABC and DEF.

    • For triangle ABC, calculate using the cross product of two vectors formed by its sides: extNormalABC=extABimesextAC ext{Normal}_{ABC} = ext{AB} imes ext{AC}

    • For triangle DEF, apply the same method: extNormalDEF=extDEimesextDF ext{Normal}_{DEF} = ext{DE} imes ext{DF}

  2. Use the dot product to find the angle: ext{cos}( heta) = rac{ ext{Normal}_{ABC} ullet ext{Normal}_{DEF}}{| ext{Normal}_{ABC}| | ext{Normal}_{DEF}|}

  3. Calculate the angle heta heta using: heta=extcos1(extcos(heta)) heta = ext{cos}^{-1}( ext{cos}( heta))

Step 4

Draw the plan and elevation of the inner triangle.

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Answer

  1. Offset triangle ABC by 10mm towards the inside of the 45° set square:

    • Adjust the coordinates of points A, B, and C accordingly.
  2. Plot the new coordinates and connect the points to form the inner triangle.

  3. Draw the plan and elevation of this inner triangle clearly distinguishing it from the outer triangle.

  4. Ensure all dimensions are labeled appropriately.

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