Photo AI
The plan, elevation and end view of an archery target are shown - Leaving Cert DCG - Question A-4 - 2017
Question A-4
The plan, elevation and end view of an archery target are shown. The line PA represents the plan of an arrow just before it hits the target. The arrow travels horiz... show full transcript
Worked Solution & Example Answer:The plan, elevation and end view of an archery target are shown - Leaving Cert DCG - Question A-4 - 2017
Step 1
(a) Draw the arrow PA in the end view and in the elevation.
Answer
To draw the arrow PA in both views:
- End View: Draw a horizontal line representing the flight path of the arrow. Mark points P and A on this line, with P on the left and A on the right, indicating the direction of travel.
- Elevation View: Draw a vertical line to represent the height of the arrow just before it hits the target. Use point P and extend it horizontally to point A. Both views should connect properly to show the relation between the end view and elevation.
Step 2
(b) Determine the projections of the arrow when it hits the target.
Answer
The projections of the arrow can be determined as follows:
- On the Plan View: The arrow hits the target at a certain point on the circular target. Draw a vertical line from point A down to the target, showing the point of impact.
- On the Elevation View: The horizontal line from P passes through the target at the corresponding height of point A. Mark this intersection clearly as the projection of the arrow on the target.
Step 3
(c) Determine the true angle between the two flight paths.
Answer
To determine the true angle between the two flight paths:
-
Identify the line from P to A (the horizontal arrow) and the line that passes through P to the bull's eye at the target.
-
Use the geometric properties to find the angle between these two lines at point P, using the tangent function if necessary. The angle can be calculated using the formula:
heta = an^{-1} rac{ ext{Opposite}}{ ext{Adjacent}}
-
Represent this angle in degrees or radians as required.