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Doctors sometimes need to work out how much medicine to give a child, based on the correct dose for an adult - Leaving Cert Mathematics - Question 7 - 2012

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Doctors sometimes need to work out how much medicine to give a child, based on the correct dose for an adult. There are different ways of doing this, based on the ch... show full transcript

Worked Solution & Example Answer:Doctors sometimes need to work out how much medicine to give a child, based on the correct dose for an adult - Leaving Cert Mathematics - Question 7 - 2012

Step 1

Calculate the child's dose using Clark's rule

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Answer

Using Clark's rule, we have:

C=W68×AC = \frac{W}{68} \times A

Substituting the values:

C=3068×125C = \frac{30}{68} \times 125

Calculating this yields:

C=37506855 mgC = \frac{3750}{68} \approx 55 \text{ mg}

Thus, the correct dose for the child weighing 30 kg is approximately 55 mg.

Step 2

Young's rule formula interpretation (i)

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Answer

For Young's rule: The formula is:

C=YY+12×AC = \frac{Y}{Y + 12} \times A

where:

  • C = child's dose
  • Y = child's age in years
  • A = adult's dose

Step 3

Young's rule formula interpretation (ii)

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Answer

For Young's rule: The formula is:

C=A×YY+12C = \frac{A \times Y}{Y + 12}

where:

  • C = child's dose
  • Y = child's age in years
  • A = adult's dose

Step 4

Young's rule formula interpretation (iii)

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Answer

For the third version of Young's rule: The formula is:

C=4×YY+12×AC = \frac{4 \times Y}{Y + 12} \times A

where:

  • C = child's dose
  • A = adult's dose
  • Y = child's age in years

Step 5

Explanation of the equivalence of the three formulas

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Answer

All three formulae can be manipulated algebraically to show they yield the same result. Specifically, rearranging each formula leads them to the common form:

C=YAY+12C = \frac{YA}{Y + 12}

This equivalence demonstrates that they all accurately compute the child's dosage based on the adult dosage adjusted by the child's age.

Step 6

Calculate the dose for a six-year-old child using Young's rule

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Answer

Using Young's rule:

C=Y×AY+12C = \frac{Y \times A}{Y + 12}

Substituting the values:

C=6×1506+12=90018=50extmgperdayC = \frac{6 \times 150}{6 + 12} = \frac{900}{18} = 50 ext{ mg per day}

Thus, the correct dose for a six-year-old child is 50 mg.

Step 7

Determine the age of the child receiving one fifth of the adult dose

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Answer

Given that the child receives one fifth of the adult dose:

Using Young's rule,

C=YAY+12C = \frac{YA}{Y + 12}

Since C is one fifth of the adult dose:

rac{A}{5} = \frac{YA}{Y + 12}

This leads to:

\Rightarrow YA = 4C$$ Given that A is 150 mg: $\Rightarrow 30Y = 150Y + 360 = 150Y$ Y = 3 years. Hence, the child is 3 years old.

Step 8

Calculate child's BSA dose for 125 cm height and 26 kg weight

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Answer

Using the BSA rule to calculate the correct dose:

C=BSA173×AC = \frac{\text{BSA}}{173} \times A

From the chart, at height of 125 cm and weight of 26 kg, the BSA is approximately 0.95 m²:

C=0.95173×200C = \frac{0.95}{173} \times 200

Calculating this gives:

110mg \approx 110 mg

So, the correct dose using BSA is approximately 110 mg.

Step 9

Find the weight and height of a nine-year-old child based on dosage rules

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Answer

Given:

  • Clark's and Young's rules both give a dose of 90 mg.
  • BSA gives a dose of 130 mg.

Based on Young's rule and solving:

Also, from Clark's, $$W = \frac{C \times 68}{A} = \frac{90 \times 68}{210} \approx 29.1 ext{ kg}\ Height can be derived from the BSA rule which relates to approximately 142 cm height. Thus: - Weight: 29.1 kg - Height: 142 cm.

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