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The figure ABCDE shown in the diagram consists of a large square ACDE standing on the diagonal [AC] of a smaller square ABCF - Leaving Cert Mathematics - Question (b) - 2021

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Question (b)

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The figure ABCDE shown in the diagram consists of a large square ACDE standing on the diagonal [AC] of a smaller square ABCF. The smaller square has a side length of... show full transcript

Worked Solution & Example Answer:The figure ABCDE shown in the diagram consists of a large square ACDE standing on the diagonal [AC] of a smaller square ABCF - Leaving Cert Mathematics - Question (b) - 2021

Step 1

Find |AC|

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Answer

To find the length of diagonal |AC| in the square ABCF, we can use the Pythagorean theorem.

Since both sides of the smaller square measure 2 cm, we have:

AC=(2)2+(2)2=4+4=8=22|AC| = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}

Step 2

Find the Area

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Answer

The area of the figure ABCDE can be calculated using the formula for the area of a square:

Area=12×(side length of square ACDE)×(height from A to C)\text{Area} = \frac{1}{2} \times (\text{side length of square ACDE}) \times (\text{height from A to C})

The height from point A to C is equal to the length of the diagonal |AC|:

Area=12×(2×2)=2×8=10 cm2\text{Area} = \frac{1}{2} \times (2 \times 2) = 2 \times \sqrt{8} = 10 \text{ cm}^2

Step 3

Find the Perimeter

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Answer

The perimeter of figure ABCDE can be found by adding all the sides:

Perimeter=2+2+AC+CD\text{Perimeter} = 2 + 2 + |AC| + |CD| Since |CD| is also 2 cm, we have:

Perimeter=2+2+2+22=4+22\text{Perimeter} = 2 + 2 + 2 + 2\sqrt{2} = 4 + 2\sqrt{2}

Calculating it numerically, we find:

Perimeter4+2×1.414=4+2.828=6.828 cm\text{Perimeter} \approx 4 + 2 \times 1.414 = 4 + 2.828 = 6.828 \text{ cm}

Therefore, rounding to two decimal places, the perimeter is approximately 12.49 cm.

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