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A field is divided into eight sections as shown below - Leaving Cert Mathematics - Question 5 - 2017

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A field is divided into eight sections as shown below. The width of each section is 3 metres. The height, in metres, of each section is given in the diagram. Use the... show full transcript

Worked Solution & Example Answer:A field is divided into eight sections as shown below - Leaving Cert Mathematics - Question 5 - 2017

Step 1

Use this information to find the value of the height marked x on the diagram.

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Answer

To find the height xx, we can use the area equation derived from the trapezoidal rule. Given:

1456=12×4×(6.4+6.9+6+6+x+2)145-6 = \frac{1}{2} \times 4 \times (6.4 + 6.9 + 6 + 6 + x + 2)

We can simplify the equation:

  • First calculate the sum of heights:
  • Total heights evaluated = 6.4 + 6.9 + 6 + 6 + 2 = 27.3
  • Plugging this into the formula results in:

139=12×4×(27.3+x)139 = \frac{1}{2} \times 4 \times (27.3 + x)

This simplifies to:

139=2(27.3+x)139 = 2(27.3 + x)

Expanding this yields:

139=54.6+2x139 = 54.6 + 2x

Isolating xx:

2x=13954.6=84.42x = 139 - 54.6 = 84.4 x=84.42=42.2x = \frac{84.4}{2} = 42.2

Thus, the value of the height marked xx is approximately 42.2 m.

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