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A local sports club is planning to run a weekly jackpot - Leaving Cert Mathematics - Question 6 - 2016

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A local sports club is planning to run a weekly jackpot. To win the Jackpot of €1000, contestants must match one letter chosen from the 26 letters in the alphabet an... show full transcript

Worked Solution & Example Answer:A local sports club is planning to run a weekly jackpot - Leaving Cert Mathematics - Question 6 - 2016

Step 1

Calculate the probability that M, 3, 3 would be the winning outcome in a particular week.

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Answer

To calculate this probability, we consider that there are 26 letters and the numbers range from 0 to 9. The selection of the letter M and the numbers 3 and 3 can be expressed as follows:

The total possible outcomes for the letter and numbers are represented as:

P(M,3,3)=126×110×110=12600P(M, 3, 3) = \frac{1}{26} \times \frac{1}{10} \times \frac{1}{10} = \frac{1}{2600}

Thus, the probability that M, 3, 3 is the winning outcome is ( \frac{1}{2600} ).

Step 2

If a contestant matches the letter only, or the letter and one number (but not both numbers), they will win €50. Using the table below, or otherwise, find how much the club should expect to make or lose on each play.

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Answer

To calculate the expected loss or gain per play:

  1. Win Jackpot:

    • Payout: €1000
    • Probability: ( P(Matching) = \frac{1}{2600} )
    • Expected Value: ( 1000 \times \frac{1}{2600} = \frac{1000}{2600} \approx 0.385 )
  2. Match letter and first number only:

    • Payout: €50
    • Probability: ( P = \frac{9}{2600} )
    • Expected Value: ( 50 \times \frac{9}{2600} = \frac{450}{2600} \approx 0.173 )
  3. Match letter and second number only:

    • Same calculation as above, so ( 0.173 ).
  4. Match letter and neither number:

    • Payout: €50
    • Probability: ( P = \frac{81}{2600} )
    • Expected Value: ( 50 \times \frac{81}{2600} = \frac{4050}{2600} \approx 1.558 )
  5. Fail to win:

    • No payout, probability: ( P = 1 - (sum \ of \ previous \ probabilities) = \frac{2500}{2600} )
    • Expected Value: ( 0 )

Total expectation:
Sum up all expected values: E(X)=0.385+0.173+0.173+1.558+0=595026002.288E(X) = 0.385 + 0.173 + 0.173 + 1.558 + 0 = \frac{5950}{2600} \approx 2.288 Since the club charges €2, the club loses approximately 29 cents per play.

Step 3

If the club wants to make an average profit of €600 per week from the lotto, how much should the club charge per play?

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Answer

To find the price per play, we set up the equation:

Let the charge per play be ( x ).

The total income per week is ( 845 \times x ). The total payout for losses is formulated as:

Profit=IncomePayouts\text{Profit} = \text{Income} - \text{Payouts}

In our case, for an average profit of €600:

845x(2.288×845)=600845x - (2.288 \times 845) = 600

Solving for ( x ):

  1. Calculate total payout:
    ( 2.288 \times 845 ) evaluating gives us around €1939.76.
  2. Insert back into the equation: ( 845x - 1939.76 = 600 )
    ( 845x = 600 + 1939.76 )
    ( 845x = 2539.76 ) ( x = \frac{2539.76}{845} \approx 3.00 )

Thus, the club should charge approximately €3.00 per play.

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