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A shopkeeper bought 25 school blazers at €30 each and 25 trousers at €20 each - Leaving Cert Mathematics - Question 1 - 2014

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A shopkeeper bought 25 school blazers at €30 each and 25 trousers at €20 each. (a) Find the total cost to the shopkeeper. (b) The shopkeeper sells a blazer and a t... show full transcript

Worked Solution & Example Answer:A shopkeeper bought 25 school blazers at €30 each and 25 trousers at €20 each - Leaving Cert Mathematics - Question 1 - 2014

Step 1

Find the total cost to the shopkeeper.

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Answer

To find the total cost to the shopkeeper, we calculate:

  1. Cost of Blazers: Number of blazers = 25, Price per blazer = €30 Therefore, total cost for blazers = 25 × €30 = €750.

  2. Cost of Trousers: Number of trousers = 25, Price per trouser = €20 Therefore, total cost for trousers = 25 × €20 = €500.

  3. Total Cost: Total cost = Cost of blazers + Cost of trousers = €750 + €500 = €1250.

Step 2

Find her profit on this transaction.

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Answer

The selling price for a blazer and trousers set is €89.95. The cost of one blazer and one trouser is:

  • Cost of Blazer: €30
  • Cost of Trouser: €20

Total cost for the set = €30 + €20 = €50.

Now, to find the profit:

  • Profit = Selling price - Cost price = €89.95 - €50 = €39.95.

Step 3

Find her mark up (profit as a percentage of cost price) on the total transaction.

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Answer

To find the total transaction details:

  1. Selling Price of 22 Sets: Selling price per set = €89.95 Thus, total for 22 sets = 22 × €89.95 = €1978.90.

  2. Selling Price of Remaining 3 Sets: Discount on selling price = 20%. Therefore, discounted price = €89.95 × (1 - 0.20) = €71.96 per set. Total for 3 sets = 3 × €71.96 = €215.88.

  3. Total Revenue: Total revenue from all sets = €1978.90 + €215.88 = €2194.78.

  4. Cost of 25 Sets: Cost price of 25 sets = Total cost to the shopkeeper = €1250.

  5. Total Profit: Total profit = Total revenue - Cost price = €2194.78 - €1250 = €944.78.

  6. Markup Percentage: Markup percentage = (Profit / Cost price) × 100 = (€944.78 / €1250) × 100 ≈ 75.58%.

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