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Question 9
In engineering, a crank-and-slider mechanism can be used to change circular motion into motion back and forth in a straight line. In the diagrams below, the crank [... show full transcript
Step 1
Answer
To find ( LCO ), we can apply the sine rule in triangle ( LCO ):
[ \frac{10}{\sin 15^\circ} = \frac{LCO}{\sin x} ]
This can be rearranged to:
[ LCO = \frac{10 \cdot \sin x}{\sin 15^\circ} ]
Calculating for ( x ) gives:
[ \sin x = \frac{10 \cdot \sin 15^\circ}{30} \approx 0.77645 ]
Taking the arcsine yields:
[ x \approx 51^\circ ]
Therefore, ( LCO ) is approximately ( 51^\circ ).
Step 2
Step 3
Step 4
Answer
Using the values from the table, we would plot the points (0, 30), (90, 18.28), (180, 10), (270, 18.28), and (360, 30) on a graph. The graph will illustrate the behavior of ( f(\alpha) ), which increases and decreases according to the sinusoidal nature of the crank's motion.
Step 5
Answer
Referring to the steepness of the graph plotted from table values, Diagram 2 shows the steepest slope at ( \alpha = 90^\circ ). This indicates that a 1 degree change in angle ( \alpha ) will result in a substantial change in the position of [C]. Therefore, Diagram 2 is the correct position.
Step 6
Answer
From the cosine rule applied to triangle ( AOB ):
[ r^2 = |AB|^2 + |AX|^2 - 2 |AB| |AX| \cos(10^\circ) ]
Substituting the values:
[ r^2 = 36^2 + 31^2 - 2 \times 36 \times 31 \times \cos(10^\circ) ]
Calculating yields: [ r \approx 7 , cm \text{ (to the nearest cm)} ]
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