Construct the triangle ABC, where |AB| = 10 cm, |\angle AB| = 60° and |\angle ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018
Question 6
Construct the triangle ABC, where |AB| = 10 cm, |\angle AB| = 60° and |\angle ABC| = 40°. Label each vertex clearly.
Measure |BC|, and write your answer in cm, corr... show full transcript
Worked Solution & Example Answer:Construct the triangle ABC, where |AB| = 10 cm, |\angle AB| = 60° and |\angle ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018
Step 1
Construct the triangle ABC
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Answer
To draw triangle ABC:
Start by drawing line segment AB measuring 10 cm.
At point A, use a protractor to measure an angle of 60° and draw a ray towards the left. This will start forming angle CAB.
At point B, also use the protractor to measure an angle of 40° and draw a ray towards the right. This will start forming angle ABC.
The point where these two rays intersect is point C. Label the vertices clearly.
Step 2
Measure |BC|, and write your answer in cm, correct to 1 decimal place.
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Answer
|BC| can be measured using a ruler. After measuring, if |BC| equals 8 cm, write the final answer as:
|BC| = 8.0 cm
Step 3
Write down the value of α and the value of β.
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Answer
Given that |\angle SPQ| = 115°,
Since opposite angles in a parallelogram are equal, |\angle QRS| (which is α) will be:
α = 115°.
To find β:
The consecutive angles in a parallelogram are supplementary, hence:
β = 180° - 115° = 65°.
Step 4
Explain why the triangle PQR is congruent to triangle RSP.
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Answer
The triangles PQR and RSP are congruent by the criteria SSS (Side-Side-Side) because:
|PQ| = |SR| (Opposite sides of the parallelogram are equal).
|QR| = |PS| (Also, opposite sides of the parallelogram are equal).
The angle |\angle PQR| = |\angle RSP| = 65° (As they are alternate interior angles due to the parallel sides PS and QR)
Thus, by SSS criteria, triangle PQR is congruent to triangle RSP.
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