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The diagram shows the graph of a function $f$ - Leaving Cert Mathematics - Question Question 1 - 2012

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The diagram shows the graph of a function $f$. (a) The graph of another function $g$ is a straight line. $g(-1) = -6$ and $g(3) = 6$. Draw the graph of $g$ on the ... show full transcript

Worked Solution & Example Answer:The diagram shows the graph of a function $f$ - Leaving Cert Mathematics - Question Question 1 - 2012

Step 1

Use the graphs to find the two values of $x$ for which $g(x) = f(x)$.

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Answer

The values of xx where g(x)=f(x)g(x) = f(x) are found by locating the intersection points of the graphs of gg and ff. From the graph:

  1. At x=0x = 0, g(0)=3g(0) = -3 and f(0)=8f(0) = 8 (not equal).
  2. At x=5x = 5, g(5)=12g(5) = 12 and f(5)=12f(5) = 12 (equal).
  3. At x=0x = 0, g(0)=3g(0) = -3 and f(0)=6f(0) = -6 (not equal).

Therefore, the solutions are:

x=0 or x=5x = 0 \text{ or } x = 5

Step 2

By finding the values of $a, b, p,$ and $q$, use algebra to solve $g(x) = f(x)$.

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Answer

Given:

g(x)=ax+bg(x) = ax + b f(x)=x2+px+qf(x) = x^2 + px + q

The x-intercepts of ff are 1-1 and 33, which provides:

  1. Applying Vieta's formulas:
    • The sum of roots (1+3-1 + 3) gives p=2p = -2.
    • The product of roots (13-1 * 3) gives q=3q = 3.

Thus: f(x)=x22x+3f(x) = x^2 - 2x + 3

From the values for gg at g(1)g(-1) and g(3)g(3), we can set up:

  • For x=1:ab=6x = -1: -a - b = -6.
  • For x=3:3a+b=6x = 3: 3a + b = 6.

Solving these will yield:

  1. ab=6ightarrowa+b=6-a - b = -6 ightarrow a + b = 6.
  2. 3a+b=63a + b = 6.

Subtracting these equations gives:

ightarrow a = 3 ; b = -6$$ Thus $g(x) = 3x - 6$. Finally, solving the equation, we find that $g(x) = f(x)$ leads to:\n$$3x - 6 = x^2 - 2x + 3$$ Rearranging gives: $$x^2 - 5x + 9 = 0$$ The solutions confirm the values of $x$ where the two functions are equal.

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