Photo AI

In 2011, a new footbridge was opened at Mizen Head, the most south-westerly point of Ireland - Leaving Cert Mathematics - Question 8 - 2014

Question icon

Question 8

In-2011,-a-new-footbridge-was-opened-at-Mizen-Head,-the-most-south-westerly-point-of-Ireland-Leaving Cert Mathematics-Question 8-2014.png

In 2011, a new footbridge was opened at Mizen Head, the most south-westerly point of Ireland. The arch of the bridge is in the shape of a parabola, as shown. The len... show full transcript

Worked Solution & Example Answer:In 2011, a new footbridge was opened at Mizen Head, the most south-westerly point of Ireland - Leaving Cert Mathematics - Question 8 - 2014

Step 1

Using the co-ordinate plane, find the co-ordinates of C, the highest point of the arch.

96%

114 rated

Answer

To find the highest point of the arch, we calculate the vertex of the parabola given by the equation:

y = -0.013x² + 0.624x.

The x-coordinate of the vertex can be found using the formula:

x=b2ax = -\frac{b}{2a}

where a = -0.013 and b = 0.624.

Calculating:

x=0.6242×0.013=24.x = -\frac{0.624}{2 \times -0.013} = 24.

Now substituting x = 24 back into the parabola equation to find y:

y = -0.013(24)² + 0.624(24)

y = -0.013(576) + 14.976 = -7.488 + 14.976 = 7.488.

Thus, the co-ordinates of C are C(24, 7.488).

Step 2

Find the co-ordinates of D and E.

99%

104 rated

Answer

Given that the perpendicular distance [DE] from the arch to the walking deck is 5 metres, we can set up the equation:

y=0.013x2+0.624xy = -0.013x² + 0.624x

Setting this equal to 5:

5 = -0.013x² + 0.624x

Rearranging gives:

0.013x² - 0.624x + 5 = 0.

Using the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b² - 4ac}}{2a} where a = 0.013, b = -0.624, and c = 5, we find:

discriminant = b² - 4ac = (-0.624)² - 4(0.013)(5) = 0.389376 - 0.26 = 0.129376.

Calculating: x=0.624±0.1293762(0.013)=0.624±0.360.026.x = \frac{0.624 \pm \sqrt{0.129376}}{2(0.013)} = \frac{0.624 \, \pm \, 0.36}{0.026}.

Thus:

  1. x1=37.8x_1 = 37.8 and D(10,5)D(10, 5).
  2. x2=10.15x_2 = 10.15 and E(38,5)E(38, 5).

Step 3

Using integration, find the area of the shaded region, ABED.

96%

101 rated

Answer

The area under the curve from A to B can be calculated using the definite integral:

Area=048(ycurveydeck)dx\text{Area} = \int_0^{48} (y_{curve} - y_{deck}) \, dx

where y_{deck} = 5 for DE.

So,

Area=048(0.013x2+0.624x5)dx\text{Area} = \int_0^{48} (-0.013x² + 0.624x - 5) \, dx
Calculating the integral:

  1. Find the integral of the equation: (0.013x2+0.624x5)dx=[0.00433x3+0.312x25x]048\int (-0.013x² + 0.624x - 5) \, dx =\left[-0.00433x^{3} + 0.312x^2 - 5x \right]_0^{48}
  2. Evaluate from 0 to 48:

=[0.00433(48)3+0.312(48)25(48)][0]= [-0.00433(48)^{3} + 0.312(48)^{2} - 5(48)] - [0] 3. Calculate the area:

Approximate answers lead to the final area under the curve, giving an area of about 194 m².

Step 4

Write the equation of the parabola in the specified form.

98%

120 rated

Answer

To convert the equation from part (a) to the form y - k = p(x - h)², we need to analyze the vertex information we found earlier (C = (24, 7.488)).

Thus, we have:

k=7.488, h=24.k = 7.488, \ h = 24.

Now, using the known elements, we can find the leading coefficient p:

The equation transforms as follows:

  1. Start from the general form: y = a(x - 24)² + 7.488,
  2. Find a by substituting another point, if needed, or rely on the original equation.

The complete equation becomes:

y - 7.488 = p(x - 24)².

Step 5

Write down the equation of a parabola given the conditions.

97%

117 rated

Answer

For the parabola with a coefficient of x² as -2 and maximum point at (3, -4), we start with the vertex form:

y - k = p(x - h)², where h = 3 and k = -4.

Since the coefficient of x² is negative, the equation will be of the form:

y+4=2(x3)2.y + 4 = -2(x - 3)².

Rearranging gives:

y = -2(x - 3)² - 4.$$

This represents the required parabola.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;