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The graph of the function $f(x) = 3^x$, where $x \in \mathbb{R}$, cuts the y-axis at $(0, 1)$ as shown in the diagram below - Leaving Cert Mathematics - Question 2 - 2019

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The-graph-of-the-function-$f(x)-=-3^x$,-where-$x-\in-\mathbb{R}$,-cuts-the-y-axis-at-$(0,-1)$-as-shown-in-the-diagram-below-Leaving Cert Mathematics-Question 2-2019.png

The graph of the function $f(x) = 3^x$, where $x \in \mathbb{R}$, cuts the y-axis at $(0, 1)$ as shown in the diagram below. Draw the graph of the function $g(x) = ... show full transcript

Worked Solution & Example Answer:The graph of the function $f(x) = 3^x$, where $x \in \mathbb{R}$, cuts the y-axis at $(0, 1)$ as shown in the diagram below - Leaving Cert Mathematics - Question 2 - 2019

Step 1

Draw the graph of the function $g(x) = 4x + 1$ on the diagram.

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Answer

To draw the graph of the function g(x)=4x+1g(x) = 4x + 1, we first find two or more points by substituting values for xx:

  • For x=0x = 0:
    g(0)=4(0)+1=1g(0) = 4(0) + 1 = 1
    Point: (0,1)(0, 1)

  • For x=0.5x = 0.5:
    g(0.5)=4(0.5)+1=3g(0.5) = 4(0.5) + 1 = 3
    Point: (0.5,3)(0.5, 3)

  • For x=1x = 1:
    g(1)=4(1)+1=5g(1) = 4(1) + 1 = 5
    Point: (1,5)(1, 5)

  • For x=1.5x = 1.5:
    g(1.5)=4(1.5)+1=7g(1.5) = 4(1.5) + 1 = 7
    Point: (1.5,7)(1.5, 7)

  • For x=2x = 2:
    g(2)=4(2)+1=9g(2) = 4(2) + 1 = 9
    Point: (2,9)(2, 9)

Plot these points on the graph and connect them to represent the linear function.

Step 2

Use substitution to verify that $f(x) < g(x)$, for $x = 1.9$.

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Answer

To verify that f(1.9)<g(1.9)f(1.9) < g(1.9), we first calculate both functions:

  1. Calculate f(1.9)f(1.9):

    f(1.9)=31.911.166f(1.9) = 3^{1.9} \approx 11.166

  2. Calculate g(1.9)g(1.9):

    g(1.9)=4(1.9)+1=8.6+1=9.6g(1.9) = 4(1.9) + 1 = 8.6 + 1 = 9.6

Now, we compare the two values:

11.166<9.611.166 < 9.6

This inequality is false; therefore, let's ensure we calculate correctly again:

Actually, f(1.9)f(1.9) is greater than g(1.9)g(1.9). Hence it shows that for x=1.9x = 1.9, the inequality does not hold, and we conclude that f(x)g(x)f(x) \geq g(x) at this value.

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