Using the properties of logarithms:
First, we split the logarithm:
loga169a2=loga(9a2)−loga(16)
Next, we express each term separately:
- For loga(9a2):
- This can be split as:
loga9+logaa2
- From loga9, since 9=32, we have:
loga9=loga(32)=2loga3=2q
- And since logaa2=2 (that is, the logarithm of a number to its own base):
logaa2=2
Combining these gives us:
loga(9a2)=2q+2
- For loga(16):
- Since 16=24, we have:
loga16=loga(24)=4loga2=4p
Combining the two parts:
loga169a2=(2q+2)−4p=2q+2−4p