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(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW - Leaving Cert Mathematics - Question 3 - 2018

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(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW. Each letter is used only once. (ii) Find the number of... show full transcript

Worked Solution & Example Answer:(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW - Leaving Cert Mathematics - Question 3 - 2018

Step 1

Find the number of different arrangements that can be made using all the letters of the word RAINBOW.

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Answer

To find the number of different arrangements of the letters in the word 'RAINBOW', we treat all letters as distinct. Since there are 7 unique letters, the number of arrangements (permutations) can be calculated as:

7!=50407! = 5040

Thus, the number of different arrangements is 5040.

Step 2

Find the number of different 3-letter arrangements that can be made using the letters of the word RAINBOW.

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Answer

To find the number of different 3-letter arrangements, we use the combination of selecting 3 letters from the 7 available, followed by permuting them.

First, the number of ways to choose 3 letters from 7 can be expressed as:

inom{7}{3} = rac{7!}{3!(7-3)!} = 35

For each selection, the letters can be arranged in:

3!=63! = 6

Therefore, the total number of different 3-letter arrangements is:

35×6=21035 \times 6 = 210

Thus, the number of different 3-letter arrangements is 210.

Step 3

Complete the “Probability” column of the table...

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Answer

The probability of landing on each sector is calculated as the ratio of the angle of the sector to the total angle of the spinner (360°). Calculating for each sector:

  • Red: 72°: ( \frac{72}{360} = \frac{1}{5} )
  • Orange: 30°: ( \frac{30}{360} = \frac{1}{12} )
  • Yellow: 45°: ( \frac{45}{360} = \frac{1}{8} )
  • Green: 90°: ( \frac{90}{360} = \frac{1}{4} )
  • Blue: 60°: ( \frac{60}{360} = \frac{1}{6} )
  • Indigo: 18°: ( \frac{18}{360} = \frac{1}{20} )
  • Violet: 45°: ( \frac{45}{360} = \frac{1}{8} )

So, the completed table is:

ColourAngleProbabilityPrize
Red72°1/5€20
Orange30°1/12€60
Yellow45°1/8€24
Green90°1/4€8
Blue60°1/6€42
Indigo18°1/20€90
Violet45°1/8€48

Step 4

Find the expected value of the prize that a player wins if they play Rainbow.

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Answer

The expected value (E) can be calculated as follows:

E(X)=i=1n(XiP(Xi))E(X) = \sum_{i=1}^{n} (X_i \cdot P(X_i))

Where:

  • XiX_i is the prize for each color,
  • P(Xi)P(X_i) is the probability for each color.

Plugging the values into the formula:

E(X)=(2015)+(60112)+(2418)+(814)+(4216)+(90120)+(4818)E(X) = (20 \cdot \frac{1}{5}) + (60 \cdot \frac{1}{12}) + (24 \cdot \frac{1}{8}) + (8 \cdot \frac{1}{4}) + (42 \cdot \frac{1}{6}) + (90 \cdot \frac{1}{20}) + (48 \cdot \frac{1}{8})

Calculating:

  • 2015=420 \cdot \frac{1}{5} = 4
  • 60112=560 \cdot \frac{1}{12} = 5
  • 2418=324 \cdot \frac{1}{8} = 3
  • 814=28 \cdot \frac{1}{4} = 2
  • 4216=742 \cdot \frac{1}{6} = 7
  • 90120=4.590 \cdot \frac{1}{20} = 4.5
  • 4818=648 \cdot \frac{1}{8} = 6

Summing these values gives:

E(X)=4+5+3+2+7+4.5+6=31.50E(X) = 4 + 5 + 3 + 2 + 7 + 4.5 + 6 = 31.50

Therefore, the expected value of the prize is €31.50.

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