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Two circles, c₁ and c₂, intersect at the points B and X, as shown - Leaving Cert Mathematics - Question Question 1 - 2014

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Two circles, c₁ and c₂, intersect at the points B and X, as shown. The circle c₁ has diameter [AB]. The circle c₂ has diameter [BC]. The line CB is a tangent to c₁. ... show full transcript

Worked Solution & Example Answer:Two circles, c₁ and c₂, intersect at the points B and X, as shown - Leaving Cert Mathematics - Question Question 1 - 2014

Step 1

Join B to X

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Answer

Since [AB] is a diameter of c₁, angle |AXB| is inscribed in a semicircle. Therefore, by the inscribed angle theorem, it follows that: AXB=90°|AXB| = 90°.

Step 2

Consider circle c₂

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Answer

Since [BC] is a diameter of c₂, angle |XCB| is also inscribed in a semicircle. Consequently, we have: XCB=90°.|XCB| = 90°. Thus, X forms right angles with both diameters.

Step 3

Analyze angles A, X, and C

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Answer

The angles generated imply that the sum of angles |AXB| and |XCB| leads to: AXC=AXB+XCB=90°+90°=180°.|AXC| = |AXB| + |XCB| = 90° + 90° = 180°. This means points A, X, and C are collinear, proving that X lies on the line AC.

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