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Solve the equation $ ext{cos} rac{30 heta}{9} = rac{1}{2}$, for $ heta ext{ in } ext{ℝ}$, (where $ heta$ is in radians) - Leaving Cert Mathematics - Question 5 - 2010

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Solve-the-equation-$-ext{cos}--rac{30-heta}{9}-=--rac{1}{2}$,-for-$-heta--ext{-in-}--ext{ℝ}$,-(where-$-heta$-is-in-radians)-Leaving Cert Mathematics-Question 5-2010.png

Solve the equation $ ext{cos} rac{30 heta}{9} = rac{1}{2}$, for $ heta ext{ in } ext{ℝ}$, (where $ heta$ is in radians). The graphs of three functions are shown... show full transcript

Worked Solution & Example Answer:Solve the equation $ ext{cos} rac{30 heta}{9} = rac{1}{2}$, for $ heta ext{ in } ext{ℝ}$, (where $ heta$ is in radians) - Leaving Cert Mathematics - Question 5 - 2010

Step 1

Solve the equation $ ext{cos} rac{30 heta}{9} = rac{1}{2}$

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Answer

To solve the equation, we start by recognizing that ext{cos} heta = rac{1}{2} has solutions at:

heta = rac{ ext{π}}{3} + 2n ext{π} and heta = - rac{ ext{π}}{3} + 2n ext{π}, where nn is any integer.

Substituting for heta heta gives: rac{30 heta}{9} = rac{ ext{π}}{3} + 2n ext{π} and rac{30 heta}{9} = - rac{ ext{π}}{3} + 2n ext{π}.

From this, we can multiply each equation accordingly:

  1. 30 heta = 9 imes rac{ ext{π}}{3} + 18n ext{π} ightarrow heta = rac{ ext{π}}{10} + rac{3n ext{π}}{5}
  2. 30 heta = 9 imes - rac{ ext{π}}{3} + 18n ext{π} ightarrow heta = - rac{ ext{π}}{10} + rac{3n ext{π}}{5}

Thus, the solutions are: heta = rac{ ext{π}}{10} + rac{3n ext{π}}{5} and heta = - rac{ ext{π}}{10} + rac{3n ext{π}}{5} where nextisanintegern ext{ is an integer}.

Step 2

Identify Functions in part (b)

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Answer

Looking at the graph:

  • The function corresponding to the solid line (continuous) that oscillates between 1-1 and 11 is y=h(x)ightarrowxightarrowextcos3xy = h(x) ightarrow x ightarrow ext{cos } 3x.
  • The function corresponding to the dotted line (dashed) that has an amplitude of 22 is y=g(x)ightarrowxightarrow2extcos3xy = g(x) ightarrow x ightarrow 2 ext{cos } 3x.
  • The function corresponding to the dashed line that oscillates between 3-3 and 33 is y=f(x)ightarrowxightarrow3extcos2xy = f(x) ightarrow x ightarrow 3 ext{cos } 2x.

Step 3

Label the scales on the axes

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Answer

The vertical scale represents the function value ranging from 3-3 to 33 as the maximum amplitude of y=f(x)y = f(x) is 33 and the minimum is 3-3.

The horizontal scale should show the intervals for xx which corresponds to typical values for the cosine function, such as 00, rac{ ext{π}}{2}, extπ ext{π}, rac{3 ext{π}}{2}, and 2extπ2 ext{π}.

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