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The top of the Fastnet lighthouse, F, is 49 m above sea level - Leaving Cert Mathematics - Question d - 2022

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The top of the Fastnet lighthouse, F, is 49 m above sea level. The angle of elevation of the top of the lighthouse from a ship S is 1°2', as shown in the diagram bel... show full transcript

Worked Solution & Example Answer:The top of the Fastnet lighthouse, F, is 49 m above sea level - Leaving Cert Mathematics - Question d - 2022

Step 1

Find the horizontal distance marked d below, from the ship to the base of the lighthouse.

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Answer

To determine the horizontal distance, we will use the tangent function in trigonometry. The tangent of an angle in a right triangle is defined as the ratio of the opposite side to the adjacent side.

  1. Identify the relevant information from the problem:

    • Height of the lighthouse (opposite side) = 49 m
    • Angle of elevation = 1°2'
  2. Write the equation that relates the tangent of the angle to the opposite and adjacent sides: an(1exto2)=49d an(1^{ ext{o}} 2') = \frac{49}{d}

  3. Rearrange this equation to solve for d: d=49tan(1exto2)d = \frac{49}{\tan(1^{ ext{o}} 2')}

  4. Calculate the value of an(1exto2) an(1^{ ext{o}} 2') using a calculator:

    • Convert the angle 1°2' to decimal form:
      • 1exto2=1+260=1.0333exto1^{ ext{o}} 2' = 1 + \frac{2}{60} = 1.0333^{ ext{o}}
    • Now compute an(1.0333exto)eq0.0175 an(1.0333^{ ext{o}}) eq 0.0175
  5. Plug this value back into the equation for d:

eq 2799 ext{ m}$$

  1. Convert distance from meters to kilometers: d=27991000=2.799extkmd = \frac{2799}{1000} = 2.799 ext{ km}

  2. Round to 2 decimal places: d2.80extkmd \approx 2.80 ext{ km}

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