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Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65° - Leaving Cert Mathematics - Question 6 - 2019

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Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65°. The point P has been marked in for you. Show all your construction lines, a... show full transcript

Worked Solution & Example Answer:Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65° - Leaving Cert Mathematics - Question 6 - 2019

Step 1

Construct the parallelogram P Q R S

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Answer

  1. Begin by placing the point P on a straight horizontal line.
  2. Using a protractor, measure an angle of 65° from point P and mark this position as S.
  3. From point P, measure a length of 5 cm and mark point S.
  4. From point S, draw a line parallel to P Q for a length of 9 cm to locate point R.
  5. Finally, connect points Q and R to complete the parallelogram. Ensure to label all points clearly.

Step 2

Find the area of the parallelogram P Q R S

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Answer

The area A of a parallelogram can be calculated using the formula:

A=bimeshA = b imes h

where:

  • b is the base (length |P Q| = 9 cm)
  • h is the height, which can be calculated as:

h=PSimesextsin(heta)h = |P S| imes ext{sin}( heta)

where heta=65° heta = 65° and |P S| = 5 cm.

Calculating height:

\approx 5 imes 0.9063 \ \\ \approx 4.5319 ext{ cm}$$ Now substituting back into the area formula: $$A = 9 imes 4.5319 \ \\ \approx 40.7871 ext{ cm}^2$$ Rounding to 2 decimal places, the area is approximately 40.79 cm².

Step 3

Find the value of α and the value of β

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Answer

From the diagram, we know:

  1. The angle ∠WXY at the circle is related to angle ∠WOS at the center: ∠WXY = 1/2 ∠WOS.

Since ∠WXY = 52°, we can deduce:

2β=52°2β = 52°

Thus, β=26°β = 26°.

  1. To find α, using the property of a circle, angles subtended by the same chord are equal:

Since angle at the center is double that at the circumference:

α=52°α = 52°

Therefore, we have:

  • α = 52°
  • β = 26°.

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