Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65° - Leaving Cert Mathematics - Question 6 - 2019
Question 6
Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65°.
The point P has been marked in for you.
Show all your construction lines, a... show full transcript
Worked Solution & Example Answer:Construct the parallelogram P Q R S, where |P Q| = 9 cm, |P S| = 5 cm and |∠S P Q| = 65° - Leaving Cert Mathematics - Question 6 - 2019
Step 1
Construct the parallelogram P Q R S
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Answer
Begin by placing the point P on a straight horizontal line.
Using a protractor, measure an angle of 65° from point P and mark this position as S.
From point P, measure a length of 5 cm and mark point S.
From point S, draw a line parallel to P Q for a length of 9 cm to locate point R.
Finally, connect points Q and R to complete the parallelogram. Ensure to label all points clearly.
Step 2
Find the area of the parallelogram P Q R S
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Answer
The area A of a parallelogram can be calculated using the formula:
A=bimesh
where:
b is the base (length |P Q| = 9 cm)
h is the height, which can be calculated as:
h=∣PS∣imesextsin(heta)
where heta=65° and |P S| = 5 cm.
Calculating height:
\approx 5 imes 0.9063 \ \\
\approx 4.5319 ext{ cm}$$
Now substituting back into the area formula:
$$A = 9 imes 4.5319 \ \\
\approx 40.7871 ext{ cm}^2$$
Rounding to 2 decimal places, the area is approximately 40.79 cm².
Step 3
Find the value of α and the value of β
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Answer
From the diagram, we know:
The angle ∠WXY at the circle is related to angle ∠WOS at the center: ∠WXY = 1/2 ∠WOS.
Since ∠WXY = 52°, we can deduce:
2β=52°
Thus, β=26°.
To find α, using the property of a circle, angles subtended by the same chord are equal:
Since angle at the center is double that at the circumference:
α=52°
Therefore, we have:
α = 52°
β = 26°.
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