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(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018

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(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40°. Label each vertex clearly. (ii) Measure |BC|, and write your answer in cm, co... show full transcript

Worked Solution & Example Answer:(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018

Step 1

Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40°. Label each vertex clearly.

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Answer

  1. Start by drawing a line segment |AB| of 10 cm.

  2. At point A, use a compass to draw an angle of 60° to create the line |AC|.

  3. At point B, draw another angle of 40° to create the line |BC|.

  4. Extend lines |AC| and |BC| until they intersect at point C.

  5. Label the vertices clearly as A, B, and C.

Step 2

Measure |BC|, and write your answer in cm, correct to 1 decimal place.

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Answer

Using a ruler, measure the length of line segment |BC|. After measurement, you find |BC| = 8 cm.

Step 3

Write down the value of α and the value of β.

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Answer

Given that |∠SPQ| = 115°,

  1. Since the opposite angles in a parallelogram are equal, we have:
    • α = 115°
  2. The sum of angles in a triangle equals 180°, thus:
    • β = 180° - |∠SPQ| = 180° - 115° = 65°.

Step 4

Explain why the triangle PQR is congruent to triangle RSP.

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Answer

The triangles PQR and RSP are congruent due to the following reasons:

  1. Both triangles share side |PR|, which is common to both triangles.

  2. The angles |∠PQR| and |∠RSP| are equal to 65°.

  3. Lastly, |QR| = |PS| because they are opposite sides of the parallelogram.

Thus, by the Side-Angle-Side (SAS) congruence criterion, triangle PQR is congruent to triangle RSP.

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