(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018
Question 6
(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40°. Label each vertex clearly.
(ii) Measure |BC|, and write your answer in cm, co... show full transcript
Worked Solution & Example Answer:(a) (i) Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40° - Leaving Cert Mathematics - Question 6 - 2018
Step 1
Construct the triangle ABC, where |AB| = 10 cm, |∠CAB| = 60° and |∠ABC| = 40°. Label each vertex clearly.
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Answer
Start by drawing a line segment |AB| of 10 cm.
At point A, use a compass to draw an angle of 60° to create the line |AC|.
At point B, draw another angle of 40° to create the line |BC|.
Extend lines |AC| and |BC| until they intersect at point C.
Label the vertices clearly as A, B, and C.
Step 2
Measure |BC|, and write your answer in cm, correct to 1 decimal place.
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Answer
Using a ruler, measure the length of line segment |BC|. After measurement, you find |BC| = 8 cm.
Step 3
Write down the value of α and the value of β.
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Answer
Given that |∠SPQ| = 115°,
Since the opposite angles in a parallelogram are equal, we have:
α = 115°
The sum of angles in a triangle equals 180°, thus:
β = 180° - |∠SPQ| = 180° - 115° = 65°.
Step 4
Explain why the triangle PQR is congruent to triangle RSP.
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Answer
The triangles PQR and RSP are congruent due to the following reasons:
Both triangles share side |PR|, which is common to both triangles.
The angles |∠PQR| and |∠RSP| are equal to 65°.
Lastly, |QR| = |PS| because they are opposite sides of the parallelogram.
Thus, by the Side-Angle-Side (SAS) congruence criterion, triangle PQR is congruent to triangle RSP.
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