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State Faraday's law of electromagnetic induction - Leaving Cert Physics - Question 10 - 2016

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State Faraday's law of electromagnetic induction. Describe an experiment to demonstrate this law. Derive an expression for the effective resistance of two resistors... show full transcript

Worked Solution & Example Answer:State Faraday's law of electromagnetic induction - Leaving Cert Physics - Question 10 - 2016

Step 1

State Faraday's law of electromagnetic induction.

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Answer

Faraday's law of electromagnetic induction states that the electromotive force (emf) induced in a coil is proportional to the rate of change of magnetic flux through the coil. The equation can be expressed as:

ext{emf} = - rac{d heta}{dt}

where ( heta ) is the magnetic flux.

Step 2

Describe an experiment to demonstrate this law.

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Answer

To demonstrate Faraday's law, one can set up an experiment with a coil wrapped around a magnet. By moving the magnet quickly in and out of the coil, an emf is induced, which can be measured with a galvanometer. The faster the magnet moves, the greater the reading on the galvanometer, demonstrating that a change in magnetic flux induces current.

Step 3

Derive an expression for the effective resistance of two resistors in parallel.

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Answer

The effective resistance ( R_{eq} ) of two resistors in parallel, ( R_1 ) and ( R_2 ), can be derived using the formula:

1Req=1R1+1R2\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}

By rearranging, we obtain:

Req=R1R2R1+R2R_{eq} = \frac{R_1 \cdot R_2}{R_1 + R_2}

Step 4

Calculate the current in (i) the coil.

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Answer

For the coil, using Ohm's law, we can find the current ( I_c ):

Rtotal=200Ω V=120V Ic=VRtotal=120200=0.6AR_{total} = 200 \Omega \ V = 120 V \ I_c = \frac{V}{R_{total}} = \frac{120}{200} = 0.6 A

Step 5

Calculate the current in (ii) the 50 Ω resistor.

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Answer

The effective resistance of the parallel combination is given by:

Rparallel=40Ω Rtotal=Rcoil+Rparallel=200+40=240ΩR_{parallel} = 40 \Omega \ R_{total} = R_{coil} + R_{parallel} = 200 + 40 = 240 \Omega

Using Ohm's law, the current through the 50 Ω resistor can be calculated as:

I50=120Rparallel=12040=3AI_{50} = \frac{120}{R_{parallel}} = \frac{120}{40} = 3 A

Step 6

Calculate (i) the average emf induced in the coil during the 3 ms time period.

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Answer

The average emf ( \mathcal{E} ) induced can be calculated using the formula:

E=ΔθΔt=4.5×1043×103=15000V\mathcal{E} = \frac{\Delta \theta}{\Delta t} = \frac{4.5 \times 10^{4}}{3 \times 10^{-3}} = 15000 V

Step 7

Calculate (ii) the average current in the coil during this period.

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Answer

The average current in the coil can be found using Ohm's Law:

Icoil=ERcoil=15000200=75AI_{coil} = \frac{\mathcal{E}}{R_{coil}} = \frac{15000}{200} = 75 A

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