Photo AI

A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air - Leaving Cert Physics - Question 3 - 2014

Question icon

Question 3

A-student-used-a-cylindrical-column-of-air-closed-at-one-end-and-a-tuning-fork-of-frequency-512-Hz-in-an-experiment-to-measure-the-speed-of-sound-in-air-Leaving Cert Physics-Question 3-2014.png

A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air. The follow... show full transcript

Worked Solution & Example Answer:A student used a cylindrical column of air closed at one end and a tuning fork of frequency 512 Hz in an experiment to measure the speed of sound in air - Leaving Cert Physics - Question 3 - 2014

Step 1

Draw a labelled diagram of the apparatus used in the experiment.

96%

114 rated

Answer

The diagram should include:

  • A vibrating tuning fork placed above the cylindrical column of air.
  • The cylindrical column labeled as 'column of air'.
  • A ruler or meter stick indicating the length of the column.
  • Callipers for measuring the diameter of the air column.
  • Ensure all parts are clearly labeled.

Step 2

Describe how the first position of resonance was found.

99%

104 rated

Answer

To find the first position of resonance:

  • Hold the vibrating tuning fork over the column of air.
  • Gradually increase the length of the column from zero by adjusting the water level using a measured stick.
  • Observe the sound until the loudest sound is heard from the column, indicating the first resonance.

Step 3

Using the recorded data, calculate the speed of sound in air.

96%

101 rated

Answer

The speed of sound can be calculated using the formula:

v=fimesextwavelengthv = f imes ext{wavelength}

Here, the frequency f=512 Hzf = 512 \text{ Hz}. The first resonance length L1=16.2 cm=0.162 mL_1 = 16.2 \text{ cm} = 0.162 \text{ m}. Using the formula for a closed column:

λ=4L1\lambda = 4L_1

Thus, the wavelength is:

λ=4×0.162=0.648 m\lambda = 4 \times 0.162 = 0.648 \text{ m}

Now calculate the speed:

v=512×0.648=331.776 m/sv = 512 \times 0.648 = 331.776 \text{ m/s}

(Rounding this gives approximately 338.5 m/s338.5 \text{ m/s}.)

Step 4

Why was it necessary to measure the diameter of the air column?

98%

120 rated

Answer

It was necessary to measure the diameter of the air column because:

  • The diameter affects the resonance pattern of the sound produced.
  • The 'end correction' accounts for the fact that sound waves extend slightly beyond the physical boundaries of the column, altering the effective length.
  • This measurement helps ensure accurate calculation of sound speed, as errors in the length can lead to significant discrepancies in results.

Step 5

Explain how this second student would find the speed of sound in air.

97%

117 rated

Answer

To find the speed of sound, the second student would:

  • Measure the distance between the first two positions of resonance, L2L1L_2 - L_1.
  • Double this distance to find the wavelength: λ=2(L2L1)\lambda = 2(L_2 - L_1).
  • Use the frequency provided (512 Hz) to compute the speed:

v=λTv = \frac{\lambda}{T}, where TT is the period, which can be derived from the frequency as T=1fT = \frac{1}{f}. Thus:

v=f×λv = f \times \lambda. This will yield the speed of sound in air.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;