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In an experiment to determine the acceleration due to gravity, a student set up a simple pendulum of length 300 mm - Leaving Cert Physics - Question 1 - 2021

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In an experiment to determine the acceleration due to gravity, a student set up a simple pendulum of length 300 mm. The student suspended the pendulum from a fixed p... show full transcript

Worked Solution & Example Answer:In an experiment to determine the acceleration due to gravity, a student set up a simple pendulum of length 300 mm - Leaving Cert Physics - Question 1 - 2021

Step 1

Draw a labelled diagram of how the apparatus was arranged in this experiment.

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Answer

To accurately depict the setup:

  • Draw a vertical string attached to a fixed point overhead.
  • At the end of the string, illustrate the bob (a small mass).
  • Label the string and bob clearly, ensuring to indicate that the string is connected to a fixed support above.

Step 2

Indicate on the diagram (a) the fixed point of suspension, (b) the distance l.

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(a) Label the fixed point of suspension as the point where the string is anchored. (b) Mark the distance l as the length of the string from the fixed point to the midpoint of the bob.

Step 3

Why did the student measure the time for 20 oscillations rather than the time for one oscillation?

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Answer

Measuring the time for 20 oscillations helps to obtain a more accurate average time. Individual oscillation measurements can be influenced by timing errors and variations in the start and stop timing. By averaging over multiple oscillations, these random errors are minimized, leading to a more reliable determination of the oscillation period.

Step 4

Use the data to draw a suitable graph to calculate the acceleration due to gravity, g.

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Answer

To graphically represent this data:

  • Plot the length l on the x-axis against the square of the time per oscillation,
  • Calculate the period for one oscillation by dividing the total time for 20 oscillations by 20 ( ext{period} = rac{t}{20}).
  • Plot the values of l on the x-axis and the corresponding values of (extperiod)2( ext{period})^2 on the y-axis.
  • Draw a line of best fit through the plotted points to determine the slope, which will be used in the next step.

Step 5

Hence determine g.

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Answer

From the slope of the graph, we have: ext{slope} = rac{g}{4 ext{π}^2} To find g, rearrange the equation: g=extslopeimes4extπ2g = ext{slope} imes 4 ext{π}^2 Substituting the slope value from the graph will yield the acceleration due to gravity g. Approximate value: gextisapproximately9.8extm/s2g ext{ is approximately } 9.8 ext{ m/s}^2.

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