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In an experiment to investigate the variation of current I with potential difference V for a copper sulfate solution, the following apparatus was used - Leaving Cert Physics - Question 4 - 2012

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In an experiment to investigate the variation of current I with potential difference V for a copper sulfate solution, the following apparatus was used. (i) Name the... show full transcript

Worked Solution & Example Answer:In an experiment to investigate the variation of current I with potential difference V for a copper sulfate solution, the following apparatus was used - Leaving Cert Physics - Question 4 - 2012

Step 1

Name the instrument X.

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Answer

The instrument X is a milliameter, which is used for measuring small electric currents.

Step 2

Name the apparatus Y and give its function in the experiment.

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Answer

The apparatus Y is a potentiometer. Its function in the experiment is to measure the potential difference (voltage) across the copper sulfate solution, ensuring that the current remains constant.

Step 3

How was the potential difference measured in the experiment?

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The potential difference was measured using a voltmeter connected in parallel to the copper sulfate solution to accurately determine the voltage across it.

Step 4

Using the data in the table, draw a graph on graph paper to show the variation of current with potential difference.

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Answer

To plot the graph, label the x-axis as '1/I (A)' and the y-axis as 'V (V)'. Plot the points based on the values from the table. Connect the points using a straight line to show the linear relationship between current and potential difference.

Step 5

Calculate the slope of your graph.

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Answer

To calculate the slope of the graph, use the formula:

ext{slope} = rac{ ext{change in } V}{ ext{change in } I} = rac{5.0 - 0.0}{2.0 - 0.0} = rac{5.0}{2.0} = 2.5 ext{ V/A}

Step 6

Use this value to determine the resistance of the copper sulfate solution.

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Using Ohm's Law, which states that resistance R is equal to the potential difference V divided by the current I, we can calculate the resistance of the copper sulfate solution:

R = rac{V}{I} = rac{5.0}{2.0} = 2.5 ext{ ohms}

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