In an experiment to verify Joule's law a constant current was passed through a heating coil immersed in water - Leaving Cert Physics - Question 5 - 2021
Question 5
In an experiment to verify Joule's law a constant current was passed through a heating coil immersed in water. The current was allowed to flow for four minutes and t... show full transcript
Worked Solution & Example Answer:In an experiment to verify Joule's law a constant current was passed through a heating coil immersed in water - Leaving Cert Physics - Question 5 - 2021
Step 1
Draw a labelled diagram of how the apparatus was arranged in this experiment.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To draw the diagram:
Power Source: Include a battery or power supply.
Ammeter in Series: Place an ammeter in series with the circuit to measure current.
Heating Coil: Show the heating coil immersed in water within a container.
Water: Clearly label the water to represent the mass of 105 g.
Thermometer: Position a thermometer to measure the temperature change in the water.
Make sure to label each component clearly.
Step 2
Why was the current allowed to flow for a constant period of time?
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The current was allowed to flow for a constant period of time to:
Maintain Experimental Consistency: Keeping the time constant ensures that the measurements for temperature rise are directly comparable.
Eliminate Time as a Variable: This allows for a more accurate analysis of how changes in current affect the temperature rise without the influence of varying time durations.
Step 3
Draw a suitable graph to verify Joule's law.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To verify Joule's law:
Values for I² (current squared): Calculate I² for the given currents:
I = 1.0 A; I² = 1.0
I = 1.5 A; I² = 2.25
I = 2.0 A; I² = 4.0
I = 2.5 A; I² = 6.25
I = 3.0 A; I² = 9.0
I = 3.5 A; I² = 12.25
Labelled Axes: Label the x-axis as 'I² (A²)' and the y-axis as 'ΔΘ (°C)'.
Correct Points Plotted: Plot the calculated points on the graph.
Line of Best Fit: Draw a line of best fit to illustrate the relationship between I² and ΔΘ, confirming Joule's law.
Step 4
Use your graph to calculate the average resistance of the heating coil.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To calculate the resistance:
Slope Formula: Use the slope formula where slope = rac{ ext{ΔΘ}}{ ext{I²}}.
Value of Slope: Assume the value of the slope calculated from the graph is 2.03.
Using Joule's Law: Apply the relation:
P = R rac{ΔΘ}{mcΔt}
where
P is the power,
R is the resistance,
m is the mass of water (0.105 kg),
c is the specific heat capacity of water (4180 J/kg·K),
Δt is the time duration in seconds (240 s).
Calculate Resistance: Rearranging gives:
R = rac{m c imes ext{slope}}{P}
Substituting the values will yield:
Rextisapproximately3.71extΩ
Join the Leaving Cert students using SimpleStudy...