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A student used a narrow beam of monochromatic light and a diffraction grating to determine λ, the wavelength of the monochromatic light - Leaving Cert Physics - Question 3 - 2018

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A student used a narrow beam of monochromatic light and a diffraction grating to determine λ, the wavelength of the monochromatic light. The following data were reco... show full transcript

Worked Solution & Example Answer:A student used a narrow beam of monochromatic light and a diffraction grating to determine λ, the wavelength of the monochromatic light - Leaving Cert Physics - Question 3 - 2018

Step 1

Draw a labelled diagram of the apparatus that the student used in this experiment.

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Answer

The diagram should include:

  • A screen
  • A laser to generate the narrow beam of monochromatic light
  • A diffraction grating specifically designed for this experiment
  • An apparatus like a spectrometer for measuring the diffraction angles
  • A sodium lamp (typically used as a light source) positioned at an appropriate angle to focus on the grating.

Step 2

Describe how the angle between the two first order images was obtained.

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Answer

The angle ϕ was obtained by measuring the distances from the diffraction grating to the positions of the first order images (s1 and s2). The observer records the angle θ1 to the left from the grating and θ2 to the right. The angle ϕ then can be calculated as:

ϕ=θ1+θ2ϕ = θ_1 + θ_2

This involves making precise measurements with the spectrometer.

Step 3

Calculate the wavelength of the beam of light.

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Answer

To calculate the wavelength of the light, we can use the diffraction grating formula:

nλ=dimesextsin(θ)nλ = d imes ext{sin}(θ)

Where:

  • n = order of the image (n = 1 for first order)
  • d = distance between grating lines = ( \frac{1}{number ; of ; lines ; per ; mm} = \frac{1}{500 ; mm} = 2 \times 10^{-6} ; m )
  • θ = angle measured, which is given as 17.05°

Substituting the values:

  • Convert the angle θ to radians for calculation: θ = 17.05°
  • Calculate sin(θ): sin(17.05°)=0.292sin(17.05°) = 0.292
  • Now plug in the values:

λ=d×sin(θ)n=(2×106)×0.2921=5.86×107m λ = \frac{d \times sin(θ)}{n} = \frac{(2 \times 10^{-6}) \times 0.292}{1} = 5.86 \times 10^{-7} m

Step 4

Describe the effect on the size of the angle ϕ, the angle between the two first order images, if the diffraction grating above was replaced with a diffraction grating of 80 lines per mm.

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Answer

The angle ϕ would decrease if the diffraction grating is replaced with one having 80 lines per mm. This is because a finer grating (more lines per unit length) produces narrower diffraction patterns, thus resulting in smaller angles for the same order of diffraction.

Step 5

Hence determine which grating would give a more accurate value for λ. Justify your answer.

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The grating with 500 lines per mm would provide a more accurate value for λ. This is due to the fact that larger measurements (i.e., larger angles) lead to smaller percentage errors in calculations, as the resolution of measurement improves with a higher number of lines per mm.

Step 6

What would the student observe if the source of monochromatic light was replaced with a source of white light?

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Answer

If the source of monochromatic light is replaced with white light, the student would observe a spectrum of colors instead of a single diffraction pattern. This phenomenon occurs because white light is composed of multiple wavelengths, each of which is diffracted at different angles, resulting in a continuum of color across the screen.

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