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A student investigated the relationship between the period and the length of a simple pendulum - Leaving Cert Physics - Question 1 - 2017

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A student investigated the relationship between the period and the length of a simple pendulum. The student measured the length l of the pendulum which was then allo... show full transcript

Worked Solution & Example Answer:A student investigated the relationship between the period and the length of a simple pendulum - Leaving Cert Physics - Question 1 - 2017

Step 1

Why did the student use a small angle?

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Answer

The student used a small angle because the formula for the period of a pendulum is only valid for small angles. At larger angles, the motion no longer approximates simple harmonic motion (SHM), leading to inaccuracies in the measured period.

Step 2

How did the student ensure that the pendulum was suspended from a fixed point?

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Answer

The student ensured the pendulum was suspended from a fixed point by using a cork or two coins to hold the pendulum and allow it to swing freely.

Step 3

Between which points was the length of the pendulum measured?

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Answer

The length of the pendulum was measured from the bottom of the cork or coins to the middle of the bob.

Step 4

Which t value is most accurate? Explain your answer.

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Answer

The most accurate t value is 77.3 s. This is because it has the smallest percentage error when compared to the other measured time values.

Step 5

Draw a suitable graph to show the relationship between the length of a pendulum and its period.

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Answer

First, divide the t values by 40 and square them. Then, label the axes with 'l (m)' on the x-axis and 'T² (s²)' on the y-axis. Plot the points based on the calculated values and draw a straight line through the origin.

Step 6

Use your graph to calculate g, the acceleration due to gravity.

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Answer

To calculate g, determine the slope of the line using two points on the line. Then, substitute the slope into the formula: T2=4π2glT^2 = \frac{4\pi^2}{g}l Rearranging gives: g=4π2slopeg = \frac{4\pi^2}{\text{slope}} Substituting the slope will yield the value for g, which is approximately 9.8 m/s².

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