Sir Isaac Newton deduced that the weight of an object is due to the force of gravity - Leaving Cert Physics - Question 6 - 2014
Question 6
Sir Isaac Newton deduced that the weight of an object is due to the force of gravity.
Define force and give the unit of force.
State Newton's law of universal gravi... show full transcript
Worked Solution & Example Answer:Sir Isaac Newton deduced that the weight of an object is due to the force of gravity - Leaving Cert Physics - Question 6 - 2014
Step 1
Define force and give the unit of force.
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Answer
Force is defined as the cause of a change in motion. It is represented by the equation:
F=ma
where:
F is the force,
m is the mass,
a is the acceleration.
The unit of force is the Newton (N), which is defined as the force required to accelerate a mass of 1 kg at a rate of 1 m/s².
Step 2
State Newton's law of universal gravitation.
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Answer
Newton's law of universal gravitation states that:
The force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
This can be expressed mathematically as:
F∝r2m1m2
Step 3
Use the equation below, which is from page 56 of the Formulae and Tables booklet, to calculate, to one decimal place, the acceleration due to gravity on Mars.
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Answer
To find the acceleration due to gravity on Mars, we use the given formula:
g=r2GM
Where:
G=6.67×10−11 N m2/kg2 (gravitational constant)
M=6.4×1023 kg (mass of Mars)
r=3.4×106 m (radius of Mars)
Now substituting values:
g=(3.4×106)2(6.67×10−11)(6.4×1023)
Calculating this gives:
g ≈ 3.7 m/s² (to one decimal place).
Step 4
Give a reason for the strength of the rover's wheels.
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Answer
The wheels of the rover are not as strong as those of the vehicle that would be needed for Earth because Mars has a lower gravitational pull. The mass of the Mars rover, which is considerably lesser than that of Earth vehicles, and the less force exerted on the wheels results in the need for less robust construction.
Step 5
i) the weight of Curiosity on Earth.
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Answer
The weight of an object can be calculated using the formula:
W=mg
Where:
m=899 kg (mass of Curiosity)
g=9.8 m/s2 (acceleration due to gravity on Earth)
Thus:
W=899×9.8≈8810.2 N
Therefore, the weight of Curiosity on Earth is approximately 8810 N.
Step 6
ii) the mass of Curiosity on Mars.
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The mass of an object remains the same regardless of the gravitational field it is in. Thus, the mass of Curiosity on Mars is still:
899 kg.
Step 7
iii) the weight of Curiosity on Mars.
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To find the weight on Mars, we again use the weight formula:
W=mg
Where:
m=899 kg
g=3.7 m/s2 (acceleration due to gravity on Mars)
Thus:
W=899×3.7≈3326.3 N
So, the weight of Curiosity on Mars is approximately 3326 N.
Step 8
The Curiosity rover communicates with Earth using radio waves, which are part of the electromagnetic spectrum.
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Radio waves are part of the electromagnetic spectrum, which also includes microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves share the characteristic of traveling at the speed of light in a vacuum, allowing the Curiosity rover to send and receive signals across vast distances.
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