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In an experiment to verify the principle of conservation of momentum, a body A was set in motion with a constant velocity - Leaving Cert Physics - Question 1 - 2005

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In an experiment to verify the principle of conservation of momentum, a body A was set in motion with a constant velocity. It was then allowed to collide with a seco... show full transcript

Worked Solution & Example Answer:In an experiment to verify the principle of conservation of momentum, a body A was set in motion with a constant velocity - Leaving Cert Physics - Question 1 - 2005

Step 1

Draw a diagram of the apparatus used in the experiment.

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Answer

To draw the diagram for the apparatus, illustrate the following:

  1. An air track that is smooth to minimize friction.
  2. Two riders, representing the two trolleys that carry bodies A and B, respectively.
  3. A cork-pin or velcro for coalescing the trolleys after collision.

Step 2

Describe how the time interval of 0.2 s was measured.

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Answer

The time interval of 0.2 s was measured using a ticker tape timer. The timer works by printing dots at regular intervals. To measure 0.2 s:

  1. Set up two light gates connected to a card on the trolley.
  2. Calculate the time interval between the dots on the tape as 0.2 s (or 1/5 sec) based on the mechanism of the ticker tape.

Step 3

Calculate the velocity of the body A (i) before, (ii) after, the collision.

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Answer

(i) Before the collision: To find the velocity (v) of body A, we use the formula:
v = \frac{s}{t} = \frac{10.1 ext{ cm}}{0.2 ext{ s}} = 0.505 ext{ m s}^{-1} \approx 0.51 ext{ m s}^{-1}.

(ii) After the collision: Using the distance travelled after the collision: [ v = \frac{5.1 ext{ cm}}{0.2 ext{ s}} = 0.255 ext{ m s}^{-1} \approx 0.26 ext{ m s}^{-1} ]

Step 4

Show how the experiment verifies the principle of conservation of momentum.

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Answer

To verify the principle of conservation of momentum, calculate the total momentum before and after the collision:

  1. Before the collision:

    • Mass of body A: 520.1 g = 0.5201 kg
    • Distance travelled (s): 10.1 cm = 0.101 m
    • Momentum (p) of body A = m imes v = 0.5201 imes 0.505 = 0.263 ext{ kg m s}^{-1}.
  2. After the collision:

    • Total mass after collision (combined mass of A and B): 520.1 g + 490.0 g = 1010.1 g = 1.0101 kg.
    • Velocity after collision = 0.255 m s^{-1}
    • Total momentum = 1.0101 imes 0.255 = 0.2576 ext{ kg m s}^{-1}.

The momenta before and after can be approximated to show conservation.

Step 5

How were the effects of friction and gravity minimised in the experiment?

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Answer

To minimize the effects of friction and gravity:

  1. An air cushion or smooth surface was used to separate the track from direct contact (e.g., the air track).
  2. The trolleys were equipped with wheels that offered minimal resistance.
  3. The trolley was moved horizontally along the track with minimal incline, thus keeping gravitational effects minimal.

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