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The following is part of a student’s report on an experiment to verify the principle of conservation of momentum - Leaving Cert Physics - Question 1 - 2014

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The following is part of a student’s report on an experiment to verify the principle of conservation of momentum. “I ensured that no external forces acted on body A... show full transcript

Worked Solution & Example Answer:The following is part of a student’s report on an experiment to verify the principle of conservation of momentum - Leaving Cert Physics - Question 1 - 2014

Step 1

Draw a labelled diagram of the apparatus used in the experiment.

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Answer

The diagram should include two bodies and a track. Label the points of attachment for the two bodies, ensure a timer or motion sensor is indicated, and represent any light gates the experiment may use.

Step 2

State what measurements the student took and how these measurements were used to calculate the velocities.

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Answer

The student measured:

  • The masses of both bodies (A and B).
  • The time, through gaps, for body A to pass through a light gate, which gives an average time.
  • The length of gaps between the light gates to calculate distance.

These measurements were combined to calculate velocities using the formula: ext{Velocity} = rac{ ext{Distance}}{ ext{Time}}

Step 3

Using the recorded data, show how the experiment verifies the principle of conservation of momentum.

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Answer

Using the data provided:

  1. Calculate the momentum before the collision:

    • Momentum of body A before collision: pA=mAimesvA=0.3251extkgimes0.84extms1=0.273extkgms1p_A = m_A imes v_A = 0.3251 ext{ kg} imes 0.84 ext{ m s}^{-1} = 0.273 ext{ kg m s}^{-1}
    • Body B is at rest, so its momentum is 0.
    • Total momentum before = 0.273extkgms10.273 ext{ kg m s}^{-1}.
  2. Calculate the momentum after the collision:

    • Total mass of A and B after the collision: mtotal=0.3251extkg+0.3498extkg=0.6749extkgm_{total} = 0.3251 ext{ kg} + 0.3498 ext{ kg} = 0.6749 ext{ kg}
    • Velocity of A and B together after collision: pAB=mtotalimesvAB=0.6749imes0.41=0.277extkgms1p_{AB} = m_{total} imes v_{AB} = 0.6749 imes 0.41 = 0.277 ext{ kg m s}^{-1}
  3. This shows that momentum is conserved if the total momenta before and after the collision are equal, taking into account experimental errors.

Step 4

What are the two forces that the student needs to take account of to ensure this?

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Answer

The two forces to consider are:

  1. Weight (gravitational force) acting downwards on the bodies.
  2. Friction (between the bodies and the track).

Step 5

Describe how the student reduced the effects of these forces.

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Answer

To reduce the effects of these forces, the student could:

  • Weight: Ensure that the apparatus is level and indeed that weight does not affect the motion. If necessary, use a light-weight setup that minimizes gravitational influence.
  • Friction: Use a smooth, well-lubricated track or low-friction wheels to minimize the effect of friction.

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