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State the laws of equilibrium - Leaving Cert Physics - Question 12 - 2017

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State the laws of equilibrium. A sign weighing 400 N is suspended at the end of a uniform horizontal rod. The rod touches the wall at position X. The rod weighs 33... show full transcript

Worked Solution & Example Answer:State the laws of equilibrium - Leaving Cert Physics - Question 12 - 2017

Step 1

State the laws of equilibrium.

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Answer

  1. The sum of forces acting on an object is zero:

    F=0\sum F = 0

  2. The sum of moments about any point is zero:

    Moments=0 (clockwise)=(anti-clockwise)\sum \text{Moments} = 0 \text{ (clockwise)} = \text{(anti-clockwise)}

Step 2

Calculate the clockwise moment acting on the rod (due to the weight of the sign and the weight of the rod) about X.

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Answer

To calculate the clockwise moment about point X:

  1. Identify the forces:

    • Weight of the sign: 400 N
    • Weight of the rod: 330 N
  2. Use the formula for moments:

    Moment=Force×Distance\text{Moment} = \text{Force} \times \text{Distance}

  3. Distance from X to the sign (1.2 m) and the distance from X to the weight of the rod (0.6 m):

    Total Moment=(400)(1.2)+(330)(0.6)\text{Total Moment} = (400)(1.2) + (330)(0.6)

    Total Moment=480+198=678N m\text{Total Moment} = 480 + 198 = 678 \, \text{N m}

Step 3

Hence calculate the tension in the cable.

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To find the tension in the cable:

Using the equation for tension, considering the angle:

  1. Vertical component of the tension:

    Tsin(35°)=Total MomentT \sin(35°) = \text{Total Moment}

  2. Thus,

    T=678(1.2)sin(35°)T = \frac{678}{(1.2) \sin(35°)}

    Calculate:

    T678(1.2)(0.5736)565NT \approx \frac{678}{(1.2)(0.5736)} \approx 565 \, \text{N}

Step 4

Explain how this can happen.

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Answer

A rotating object can be in equilibrium when it has a constant angular velocity. This occurs when the net external torque acting on the object is zero, allowing it to maintain a steady rotation without accelerating. The forces acting on the object are balanced, meaning that the rotational effects of these forces cancel each other out.

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