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What is meant by latent heat? heat required to change state (without changing its temperature) Name an instrument used to measure temperature - Leaving Cert Physics - Question 9 - 2016

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What is meant by latent heat? heat required to change state (without changing its temperature) Name an instrument used to measure temperature. thermometer A glas... show full transcript

Worked Solution & Example Answer:What is meant by latent heat? heat required to change state (without changing its temperature) Name an instrument used to measure temperature - Leaving Cert Physics - Question 9 - 2016

Step 1

What is meant by latent heat?

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Answer

Latent heat is the heat required to change the state of a substance without changing its temperature.

Step 2

Name an instrument used to measure temperature.

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Answer

A thermometer is used to measure temperature.

Step 3

Calculate the energy removed from the water to reduce its temperature to 0 °C

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Answer

To calculate the energy removed, use the formula:

Q=mcΔTQ = mc\Delta T

where:

  • m=0.75kgm = 0.75 \, kg
  • c=4200Jkg1K1c = 4200 \, J \, kg^{-1} \, K^{-1} (specific heat capacity of water)
  • ΔT=200=20K\Delta T = 20 - 0 = 20 \, K (change in temperature)

Thus, the energy removed is:

Q=0.75×4200×20=63000JQ = 0.75 \times 4200 \times 20 = 63000 \, J

Step 4

Calculate the energy removed from the water to convert the water at 0 °C to ice at 0 °C

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Answer

To calculate the energy removed during the phase change from water to ice, use:

Q=mLfQ = mL_f

where:

  • m=0.75kgm = 0.75 \, kg
  • Lf=3.3×105Jkg1L_f = 3.3 \times 10^5 \, J \, kg^{-1} (latent heat of fusion of water)

Thus, the energy removed is:

Q=0.75×3.3×105=247500JQ = 0.75 \times 3.3 \times 10^5 = 247500 \, J

Step 5

Calculate the energy removed from the ice to cool the ice at 0 °C to ice at -15 °C

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Answer

To calculate the energy removed, use:

Q=mcΔTQ = mc\Delta T

where:

  • m=0.75kgm = 0.75 \, kg
  • c=2200Jkg1K1c = 2200 \, J \, kg^{-1} \, K^{-1} (specific heat capacity of ice)
  • ΔT=0(15)=15K\Delta T = 0 - (-15) = 15 \, K

Thus, the energy removed is:

Q=0.75×2200×15=24750JQ = 0.75 \times 2200 \times 15 = 24750 \, J

Step 6

How long will it take for the freezer to remove 9000 J of energy from the water?

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Answer

Using the power rating of the freezer, we can find the time taken:

P=Ett=EPP = \frac{E}{t} \Rightarrow t = \frac{E}{P}

where:

  • E=9000JE = 9000 \, J
  • P=300WP = 300 \, W

Thus, the time taken is:

t=9000300=30st = \frac{9000}{300} = 30 \, s

Step 7

Explain why the glass bottle cracks and shatters as the water freezes.

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Answer

As water freezes, it expands. This expansion can create pressure inside the glass bottle. If the pressure exceeds the strength of the glass, it leads to cracking and shattering.

Step 8

Outline the operation of a heat pump.

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Answer

A heat pump operates by extracting heat from a colder environment and transferring it to a warmer environment. It does this using a refrigerant that evaporates and absorbs heat from the cold space, then compresses it to release heat into the warmer space.

  1. The refrigerant evaporates in the evaporator, absorbing heat.
  2. The vapor is compressed, raising its temperature.
  3. The high-temperature vapor releases heat in the condenser.
  4. The refrigerant returns to a liquid state and repeats the cycle.

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