In an experiment to measure the wavelength of monochromatic light, the angles \( \Theta \) between a central bright image (\( n = 0 \)) and the first and second order images to the left and right were measured - Leaving Cert Physics - Question 3 - 2016
Question 3
In an experiment to measure the wavelength of monochromatic light, the angles \( \Theta \) between a central bright image (\( n = 0 \)) and the first and second orde... show full transcript
Worked Solution & Example Answer:In an experiment to measure the wavelength of monochromatic light, the angles \( \Theta \) between a central bright image (\( n = 0 \)) and the first and second order images to the left and right were measured - Leaving Cert Physics - Question 3 - 2016
Step 1
Describe, with the aid of a labelled diagram, how the data were obtained.
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Answer
To conduct the experiment to measure the wavelength of monochromatic light, a coherent light source, such as a vapor lamp, was used to illuminate a diffraction grating. The setup included a grating and a spectrometer.
A diagram should illustrate the following:
The arrangement of the laser (or vapor lamp) positioned to shine light onto the diffraction grating.
The distance ( D ) from the grating to the screen where the diffraction pattern is observed.
The angles ( \Theta_L ) and ( \Theta_R ) marked for the first and second-order images on both left and right sides of the central maximum, indicating how angles are measured from the central bright image.
Step 2
Use the data to calculate (i) the wavelength of the light
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To calculate the wavelength ( \lambda ) of the light using the provided data, we can use the formula derived from the diffraction grating equation:
d=2×10−6 m(d is the grating spacing) nsinΘ=d, for n=2Θ=36.2∘ (left)(d=1/500×10−3m)
First, compute ( d ) from the number of lines per mm:
d=500×1031=2×10−6 m
Then calculate ( \lambda ) using:
λ=nsinΘd
Using ( n = 2 ) and ( \Theta = 36.2^{\circ} ):
λ=2sin(36.2∘)2×10−6≈5.9×10−7 m
Step 3
Use the data to calculate (ii) the maximum number of images that could be observed.
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The maximum angle ( \Theta_{max} ) for observable images in a diffraction pattern is given by:
Θmax=90∘
Given that:
( n_{max} = \frac{d}{\lambda} = 3 ) for this configuration,
the maximum number of observable images can be calculated as follows:
[ n_{max} = 3 ]
Combining both sides produces:
[ 3 + 3 + 1 = 7 ]
Therefore, the maximum number of images that could be observed is 7.
Step 4
Explain what would happen to the positions of the images if (i) the wavelength of the light was decreased.
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If the wavelength of the light decreases, the angles ( \Theta ) for the maxima will also decrease, meaning the positions of the images will be closer together. This is due to the relationship observed in the diffraction equation where:
nλ=dsin(Θ)
A smaller ( \lambda ) results in a smaller value of ( \Theta ) for each order of maximum observed.
Step 5
Explain what would happen to the positions of the images if (ii) the diffraction grating was replaced with a diffraction grating of 300 lines per mm.
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Replacing the diffraction grating with one of 300 lines per mm would increase the grating spacing, ( d ). As a result, according to the diffraction equation:
nλ=dsin(Θ)
A larger ( d ) would allow for larger angles ( \Theta ) for each order of maximum, leading to the images being further apart. Thus, the overall spacing between the images would increase.
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