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10. Answer either part (a) or part (b) - Leaving Cert Physics - Question 10 - 2012

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10. Answer either part (a) or part (b). (a) (i) What is a positron? (6) (ii) When a positron and an electron meet two photons are produced. (6) (iii) Why are photo... show full transcript

Worked Solution & Example Answer:10. Answer either part (a) or part (b) - Leaving Cert Physics - Question 10 - 2012

Step 1

What is a positron?

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Answer

A positron is the antiparticle of the electron, having the same mass as an electron but a positive charge (+1e). It is involved in interactions where it can collide with electrons, leading to particle-antiparticle annihilation.

Step 2

When a positron and an electron meet two photons are produced.

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The equation representing this interaction is:

e+e+γ+γe^- + e^+ \rightarrow \gamma + \gamma

This denotes the annihilation of the positron and electron, resulting in the production of two photons.

Step 3

Why are photons produced in this interaction?

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Photons are produced as a result of the annihilation of the positron and electron, which converts their mass into energy, according to Einstein's mass-energy equivalence principle (E=mc²). This process conserves energy and momentum.

Step 4

Calculate the minimum frequency of the photons produced.

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To calculate the minimum frequency (ff) of the produced photons, first, determine the energy equivalent of the combined mass of the positron and electron:

E=(me+me+)c2E = (m_{e^-} + m_{e^+}) c^2

where the mass of the electron ( extit{m}) is approximately 9.10938356imes10319.10938356 imes 10^{-31} kg.

Thus, the total mass is:

mtotal=2×9.10938356×1031 kgm_{total} = 2 \times 9.10938356 \times 10^{-31} \text{ kg}

Substituting into the energy formula:

E=(2×9.10938356×1031)×(3×108)21.637×1013 JE = (2 \times 9.10938356 \times 10^{-31}) \times (3 \times 10^{8})^2 \approx 1.637 \times 10^{-13} \text{ J}

Using the relationship between energy and frequency:

E=hfE = hf

where hh is Planck's constant (6.62607015×1034extJs6.62607015 \times 10^{-34} ext{ Js}), we can rearrange to find:

f=Ehf = \frac{E}{h}

Substituting the calculated energy:

f1.637×10136.62607015×10342.47×1020 Hzf \approx \frac{1.637 \times 10^{-13}}{6.62607015 \times 10^{-34}} \approx 2.47 \times 10^{20} \text{ Hz}

Step 5

Explain why the photons produced usually have a greater frequency than your calculated minimum frequency value.

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The photons produced generally have a greater frequency due to additional energy being contributed by the motion of the colliding particles. When particles are moving, their kinetic energy converts into photon energy, resulting in photons with higher frequencies than the minimum calculated frequency.

Step 6

Why must two positrons travel at high speeds so as to collide with each other?

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Two positrons must travel at high speeds to ensure they have sufficient energy to overcome the repulsive electrostatic forces due to their identical positive charges. High speeds also increase their kinetic energy, enabling effective collisions to occur.

Step 7

How are charged particles given high speeds?

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Charged particles can be accelerated using various methods such as linear accelerators, cyclotrons, synchrotrons, and magnetic fields. These technologies apply electric and magnetic forces to impart energy to the charged particles, increasing their velocities significantly.

Step 8

Explain why two positrons cannot annihilate each other in a collision.

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Two positrons cannot annihilate each other because annihilation requires a particle-antiparticle pair, specifically an electron and a positron. Since both are positrons, there is no electron involved in the interaction to facilitate annihilation, as both carry positive charge and do not account for charge cancellation.

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