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Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022

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Benjamin Franklin began experimenting with electricity during the 18th century. (i) What is electric current? (ii) Name an instrument used to measure electric curr... show full transcript

Worked Solution & Example Answer:Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022

Step 1

What is electric current?

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Answer

Electric current is the flow of charge, typically carried by electrons, in a conductor.

Step 2

Name an instrument used to measure electric current.

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Answer

An ammeter, galvanometer, or multimeter is used to measure electric current.

Step 3

A torch contains a battery, a light bulb and a switch. Draw a circuit diagram to show how these components are connected in a torch.

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Answer

To illustrate a torch circuit, draw a simple circuit diagram. The battery is connected to the light bulb, with a switch in series. Refer to standard circuit symbols for accurate representation.

Step 4

The wires in a circuit are made of metal. Explain why.

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Answer

The wires in a circuit are made of metal because metals are good conductors of electricity due to the presence of free-moving electrons that facilitate the flow of charge.

Step 5

Name the subatomic particle that is the charge carrier in a metal.

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Answer

The charge carrier in a metal is an electron.

Step 6

A charge of 30 C passes through a wire in a time of 6 s. Calculate the current flowing in the wire.

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Answer

To calculate the current (I), use the formula: I=QtI = \frac{Q}{t} where Q is the charge and t is the time. Substituting the values, we have: I=30 C6 s=5 AI = \frac{30 \text{ C}}{6 \text{ s}} = 5 \text{ A}

Step 7

The wire has a resistance of 3 Ω. Calculate the potential difference (voltage) across the wire.

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To find the potential difference (V), use Ohm's Law: V=I×RV = I \times R where I is the current and R is the resistance. Here: V=5 A×3 Ω=15 VV = 5 \text{ A} \times 3 \text{ Ω} = 15 \text{ V}

Step 8

The 3 Ω wire is connected in parallel with another wire of resistance 2 Ω. Calculate the total resistance of the two wires in parallel.

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The formula for total resistance (R_total) in parallel is: 1Rtotal=1R1+1R2\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2}. Substituting the values: 1Rtotal=13+12=26+36=56\frac{1}{R_{total}} = \frac{1}{3} + \frac{1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} Hence, Rtotal=65=1.2 ΩR_{total} = \frac{6}{5} = 1.2 \text{ Ω}

Step 9

What is the resistance of a 3 m piece of the same wire?

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Answer

The resistance of a wire is proportional to its length. Therefore, if a 1.5 m wire has a resistance of 12 Ω, a 3 m piece would have: R=2×12 Ω=24 ΩR = 2 \times 12 \text{ Ω} = 24 \text{ Ω}.

Step 10

State the relationship between the resistance of a wire and its cross-sectional area.

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Answer

The resistance of a wire is inversely proportional to its cross-sectional area. This means that as the cross-sectional area increases, the resistance decreases, and vice versa.

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