Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022
Question 11
Benjamin Franklin began experimenting with electricity during the 18th century.
(i) What is electric current?
(ii) Name an instrument used to measure electric curr... show full transcript
Worked Solution & Example Answer:Benjamin Franklin began experimenting with electricity during the 18th century - Leaving Cert Physics - Question 11 - 2022
Step 1
What is electric current?
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Answer
Electric current is the flow of charge, typically carried by electrons, in a conductor.
Step 2
Name an instrument used to measure electric current.
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Answer
An ammeter, galvanometer, or multimeter is used to measure electric current.
Step 3
A torch contains a battery, a light bulb and a switch. Draw a circuit diagram to show how these components are connected in a torch.
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Answer
To illustrate a torch circuit, draw a simple circuit diagram. The battery is connected to the light bulb, with a switch in series. Refer to standard circuit symbols for accurate representation.
Step 4
The wires in a circuit are made of metal. Explain why.
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Answer
The wires in a circuit are made of metal because metals are good conductors of electricity due to the presence of free-moving electrons that facilitate the flow of charge.
Step 5
Name the subatomic particle that is the charge carrier in a metal.
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The charge carrier in a metal is an electron.
Step 6
A charge of 30 C passes through a wire in a time of 6 s. Calculate the current flowing in the wire.
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Answer
To calculate the current (I), use the formula:
I=tQ where Q is the charge and t is the time. Substituting the values, we have:
I=6 s30 C=5 A
Step 7
The wire has a resistance of 3 Ω. Calculate the potential difference (voltage) across the wire.
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Answer
To find the potential difference (V), use Ohm's Law:
V=I×R where I is the current and R is the resistance. Here:
V=5 A×3 Ω=15 V
Step 8
The 3 Ω wire is connected in parallel with another wire of resistance 2 Ω. Calculate the total resistance of the two wires in parallel.
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Answer
The formula for total resistance (R_total) in parallel is:
Rtotal1=R11+R21. Substituting the values:
Rtotal1=31+21=62+63=65
Hence,
Rtotal=56=1.2 Ω
Step 9
What is the resistance of a 3 m piece of the same wire?
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The resistance of a wire is proportional to its length. Therefore, if a 1.5 m wire has a resistance of 12 Ω, a 3 m piece would have:
R=2×12 Ω=24 Ω.
Step 10
State the relationship between the resistance of a wire and its cross-sectional area.
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The resistance of a wire is inversely proportional to its cross-sectional area. This means that as the cross-sectional area increases, the resistance decreases, and vice versa.
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