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Write an expression for the charge stored on one plate of a parallel plate capacitor in terms of the potential difference between the plates, their common area, the distance between them and the permittivity of the dielectric. - Leaving Cert Physics - Question f - 2015

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Write an expression for the charge stored on one plate of a parallel plate capacitor in terms of the potential difference between the plates, their common area, the ... show full transcript

Worked Solution & Example Answer:Write an expression for the charge stored on one plate of a parallel plate capacitor in terms of the potential difference between the plates, their common area, the distance between them and the permittivity of the dielectric. - Leaving Cert Physics - Question f - 2015

Step 1

Write an expression for the capacitance

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Answer

The capacitance (C) of a parallel plate capacitor can be expressed in terms of the permittivity ( ( \varepsilon )) of the dielectric material, the area (A) of the plates, and the distance (d) between them as follows:

C=εAdC = \frac{\varepsilon A}{d}

Step 2

Relate charge to capacitance and voltage

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Answer

The charge (Q) stored on one plate of the capacitor is related to capacitance and the potential difference (V) between the plates by the formula:

Q=CVQ = C \cdot V

Step 3

Substitute capacitance expression

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Answer

By substituting the expression for capacitance into the charge equation, we get:

Q=εAdVQ = \frac{\varepsilon A}{d} \cdot V

Thus, the final expression for the charge stored on one plate of the capacitor is:

Q=εAVdQ = \frac{\varepsilon A V}{d}

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