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Most modern electronic devices contain a touchscreen - Leaving Cert Physics - Question 9 - 2014

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Most modern electronic devices contain a touchscreen. One type of touchscreen is a capacitive touchscreen, in which the user's finger acts as a plate of a capacitor.... show full transcript

Worked Solution & Example Answer:Most modern electronic devices contain a touchscreen - Leaving Cert Physics - Question 9 - 2014

Step 1

Explain the underlined terms.

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Answer

  1. Capacitance: The capacitance is the ratio of charge (Q) stored on a capacitor to the potential difference (V) across it, described by the formula:

    C=QVC = \frac{Q}{V}

    It quantifies a capacitor's ability to store electrical energy.

  2. Potential difference (across it): This refers to the work done per unit charge to move a charge from one plate of the capacitor to the other. It is measured in volts (V).

  3. Electric field: An electric field is a region of space around a charged particle where other charged particles experience a force. The strength of the electric field (E) created in a capacitor can be defined as:

    E=VdE = \frac{V}{d}

    where V is the potential difference and d is the distance between the plates.

Step 2

Describe an experiment to demonstrate an electric field pattern.

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Answer

To demonstrate an electric field pattern:

  1. Set up two parallel metal plates connected to a high voltage source.
  2. Place a piece of cardboard on top of the plates, sprinkle fine iron filings over the cardboard.
  3. Turn on the voltage; the filings will align along the electric field lines, demonstrating the electric field pattern.
  4. Observe that the filings are denser between the plates and sparser further away, illustrating the field's strength.

Step 3

Calculate (i) the charge on each plate.

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Answer

Using the formula for capacitance:

C=QVC = \frac{Q}{V}

where ( C = 12 \mu F = 12 \times 10^{-6} F ) and ( V = 6 V ):

Rearranging gives:

Q=C×V=12×106F×6V=72μCQ = C \times V = 12 \times 10^{-6} F \times 6 V = 72 \mu C

Step 4

(ii) the energy stored in the capacitor.

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Answer

The energy stored in a capacitor is given by:

E=12CV2E = \frac{1}{2} C V^2

Plugging in the values:

E=12×12×106F×(6V)2=216μJE = \frac{1}{2} \times 12 \times 10^{-6} F \times (6 V)^2 = 216 \mu J

Step 5

Calculate the new capacitance.

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Answer

When the distance ( d ) is increased by a factor of three, the new capacitance ( C' ) can be calculated by:

C=C3=12μF3=4μFC' = \frac{C}{3} = \frac{12 \mu F}{3} = 4 \mu F

Step 6

State two differences between a capacitor and a battery.

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Answer

  1. Discharge Rate: A capacitor discharges faster than a battery, delivering energy rapidly, whereas a battery provides a constant current over time.
  2. Energy Storage: A capacitor stores electrostatic potential energy, while a battery stores chemical energy.

Step 7

What is meant by polarisation of light?

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Answer

Polarisation of light refers to the orientation of the oscillations of the light waves in a particular direction. When light is polarised, its waves vibrate in one plane as opposed to vibrating in multiple planes.

Step 8

Give one application of capacitors, other than in touchscreens.

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Answer

One application of capacitors is in flash circuits for cameras, where they store energy and release it quickly to generate a bright flash.

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