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State Boyle's law - Leaving Cert Physics - Question (a) - 2011

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State Boyle's law. Describe an experiment to demonstrate that the atmosphere exerts a pressure. Atmospheric pressure at the top of Mount Everest is very low at 3.0... show full transcript

Worked Solution & Example Answer:State Boyle's law - Leaving Cert Physics - Question (a) - 2011

Step 1

State Boyle's law.

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Answer

Boyle's law states that, for a fixed mass of gas kept at a constant temperature, the pressure is inversely proportional to the volume. Mathematically, this can be expressed as:

PV=kP V = k

where PP is the pressure, VV is the volume, and kk is a constant for a given amount of gas.

Step 2

Describe an experiment to demonstrate that the atmosphere exerts a pressure.

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Answer

  1. Apparatus: Use a container filled with water, such as a glass or a beaker, and a piece of cardboard or a lid.

  2. Procedure:

    • Fill the glass with water, ensuring it is full.
    • Cover the top of the glass with the cardboard or lid, ensuring it forms a tight seal.
    • Carefully invert the glass while holding the cardboard in place.
  3. Observation/Conclusion: When you release the cardboard, the water stays in the glass due to atmospheric pressure holding the cardboard against the top of the water. This experiment demonstrates that the atmosphere exerts a pressure that counteracts the force of gravity acting on the water.

Step 3

What volume of gas will be available at the top of Mount Everest, when the gas is released from the tank?

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Answer

Using Boyle's law, we can determine the available volume of gas at the top of Mount Everest. The formula is:

P1V1=P2V2P_1 V_1 = P_2 V_2

where:

  • P1=4.2×106 PaP_1 = 4.2 \times 10^6 \text{ Pa} (initial pressure),
  • V1=5.0 litresV_1 = 5.0 \text{ litres} (initial volume),
  • P2=3.0×104 PaP_2 = 3.0 \times 10^4 \text{ Pa} (pressure at the top of Mount Everest).

Rearranging the formula to solve for V2V_2 gives us:

V2=P1V1P2V_2 = \frac{P_1 V_1}{P_2}

Substituting the values:

V2=(4.2×106)(5.0)3.0×104 litres=2.1×1073.0×104700 litresV_2 = \frac{(4.2 \times 10^6)(5.0)}{3.0 \times 10^4} \text{ litres} = \frac{2.1 \times 10^7}{3.0 \times 10^4} \approx 700 \text{ litres}

Thus, approximately 700 litres of gas will be available at the top of Mount Everest when the gas is released from the tank.

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