Water has a density of 997 kg m³ - Leaving Cert Physics - Question c - 2021

To calculate the pressure due to the water at a given depth, we can use the formula:

$P = h \cdot \rho \cdot g$

where:

• $P$ is the pressure (Pa)
• $h$ is the depth of the water (m)
• $\rho$ is the density of the water (kg/m³)
• $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$)

Now, substituting the known values:

• Depth ($h$) = 214 m
• Density ($\rho$) = 997 kg/m³

The formula becomes:

$P = (214) \cdot (997) \cdot (9.8)$

Calculating this:

$P = 214 \times 997 \times 9.8 \approx 2.1 \times 10^6 \, \text{Pa}$