Photo AI

A spring has a length of 22 cm when a 2 N weight hangs from it - Leaving Cert Physics - Question c - 2020

Question icon

Question c

A-spring-has-a-length-of-22-cm-when-a-2-N-weight-hangs-from-it-Leaving Cert Physics-Question c-2020.png

A spring has a length of 22 cm when a 2 N weight hangs from it. The spring constant is 50 N m⁻¹. Calculate the natural length of the spring.

Worked Solution & Example Answer:A spring has a length of 22 cm when a 2 N weight hangs from it - Leaving Cert Physics - Question c - 2020

Step 1

Calculate the extension of the spring

96%

114 rated

Answer

Given that the spring has a length of 22 cm when a 2 N weight is applied, we can first find the extension of the spring. The extension ( s ext) can be calculated using the formula:

F=kimessF = k imes s

Here,

  • F=2extNF = 2 ext{ N}
  • k=50extNm−1k = 50 ext{ N m}^{-1}

Rearranging the equation to solve for ss gives us:

s=Fk=250=0.04extm=4extcms = \frac{F}{k} = \frac{2}{50} = 0.04 ext{ m} = 4 ext{ cm}

Step 2

Calculate the natural length of the spring

99%

104 rated

Answer

The natural length of the spring can be calculated by subtracting the extension from the length when the weight is applied. Therefore:

  • The total length with the weight is 22 cm.
  • The extension is 4 cm.

Thus, the natural length (L_{natural}) is:

Lnatural=Lcurrent−s=22extcm−4extcm=18extcmL_{natural} = L_{current} - s = 22 ext{ cm} - 4 ext{ cm} = 18 ext{ cm}

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;