Sir Isaac Newton was an English mathematician and physicist - Leaving Cert Physics - Question 6 - 2020
Question 6
Sir Isaac Newton was an English mathematician and physicist. He is widely recognised as one of the most influential scientists of all time.
Newton's first law of mo... show full transcript
Worked Solution & Example Answer:Sir Isaac Newton was an English mathematician and physicist - Leaving Cert Physics - Question 6 - 2020
Step 1
(i) Calculate the resultant (net) force on the 9 kg object in the diagram above. In what direction does it act?
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Answer
To find the resultant force on the 9 kg object, we need to consider all acting forces. The forces acting are 6 N to the right and 3 N to the left. The net force can be calculated as follows:
Fnet=Fright−Fleft=6extN−3extN=3extN
The direction of the resultant force is to the right.
Step 2
(ii) Calculate the acceleration of the 9 kg object.
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Using Newton's second law of motion, we can find the acceleration by dividing the net force by the mass of the object:
a=mFnet=9extkg3extN=0.33extms−2
Step 3
(iii) State Newton's third law of motion.
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Newton's third law of motion states that for every action, there is an equal and opposite reaction.
Step 4
(iv) Use Newton's third law to explain how a rocket takes off. (A labelled diagram may help your answer.)
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When a rocket takes off, it expels gas downwards at high speed. According to Newton's third law, this action (the downward force of gas) creates an equal and opposite reaction, pushing the rocket upwards. A labelled diagram can illustrate this by showing the rocket and the direction of the gas being expelled.
Step 5
(v) Calculate the kinetic energy of the car when it is travelling at 18 m s<sup>-1</sup>.
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Answer
The kinetic energy (KE) of an object can be calculated using the formula:
KE=21mv2
Substituting the known values:
KE=21×700extkg×(18extms−1)2=113400extJ
Step 6
(vi) Calculate the acceleration of the car.
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The acceleration (a) can be calculated using the formula:
a=tΔv=6exts18extms−1−0=3extms−2
Step 7
(vii) Calculate the net force on the car as it accelerates.
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Answer
Using Newton's second law:
Fnet=ma=700extkg×3extms−2=2100extN
Step 8
(viii) The engine of the car provides a driving force of 3000 N.
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The net force acts in conjunction with the driving force provided by the engine.
Step 9
(ix) Calculate the friction acting on the car.
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