Photo AI

Electrons are emitted from metals during photoelectric emission, thermionic emission and radioactive decay - Leaving Cert Physics - Question 8 - 2019

Question icon

Question 8

Electrons-are-emitted-from-metals-during-photoelectric-emission,-thermionic-emission-and-radioactive-decay-Leaving Cert Physics-Question 8-2019.png

Electrons are emitted from metals during photoelectric emission, thermionic emission and radioactive decay. Distinguish between photoelectric and thermionic emissi... show full transcript

Worked Solution & Example Answer:Electrons are emitted from metals during photoelectric emission, thermionic emission and radioactive decay - Leaving Cert Physics - Question 8 - 2019

Step 1

Distinguish between photoelectric and thermionic emission.

96%

114 rated

Answer

Photoelectric emission occurs when photons of sufficient energy strike a metal surface, causing the ejection of electrons. This process is dependent on the frequency of the incident radiation.

Thermionic emission, on the other hand, refers to the emission of electrons from a heated material due to thermal energy. This occurs when the electrons gain enough energy to overcome the material's work function.

Step 2

What name is given to electrons emitted during radioactive decay?

99%

104 rated

Answer

The electrons emitted during radioactive decay are called beta particles.

Step 3

What is a line emission spectrum? Explain, in terms of the structure of the atom, how this spectrum is produced.

96%

101 rated

Answer

A line emission spectrum is produced when an element emits light of specific wavelengths, resulting in distinct lines on a spectrum.

This occurs in an atom when electrons transition between energy levels. When an electron moves from a higher energy level to a lower energy level, it emits a photon of light. The emitted photon corresponds to a specific energy difference between the two levels, leading to a specific wavelength.

Step 4

Write down Einstein's photoelectric equation.

98%

120 rated

Answer

Einstein's photoelectric equation is given by:

Ek=hfextWorkFunctionE_k = hf - ext{Work Function}

where EkE_k is the kinetic energy of the emitted electron, hh is Planck's constant, and ff is the frequency of the incident light.

Step 5

What physical quantity is represented by (i) point A, (ii) the slope of the graph?

97%

117 rated

Answer

(i) Point A represents the threshold frequency, which is the minimum frequency needed to eject electrons from the metal surface.

(ii) The slope of the graph represents Planck's constant (h), indicating the relationship between the kinetic energy of emitted electrons and the frequency of the incident radiation.

Step 6

Calculate the maximum velocity of the emitted electrons when photons of energy 4.15 eV are incident on magnesium.

97%

121 rated

Answer

First, we calculate the kinetic energy of the emitted electrons using the photoelectric equation.

Since the work function of magnesium is 3.68 eV:

Ek=4.15exteV3.68exteV=0.47exteVE_k = 4.15 ext{ eV} - 3.68 ext{ eV} = 0.47 ext{ eV}.

To find the maximum velocity, we convert kinetic energy into joules:

E_k = rac{1}{2}mv^2

where mm is the mass of the electron, approximately 9.1imes1031extkg9.1 imes 10^{-31} ext{ kg}.

Rearranging gives:

v = ext{sqrt}igg( rac{2E_k}{m}igg = ext{sqrt}igg( rac{2 imes 0.47 imes 1.6 imes 10^{-19}}{9.1 imes 10^{-31}}igg

Calculating yields the maximum velocity of the emitted electrons.

Step 7

Where in the tube are the electrons produced?

96%

114 rated

Answer

Electrons are produced at the cathode in the X-ray tube.

Step 8

What is the minimum wavelength of an X-ray produced in a 50 kV tube?

99%

104 rated

Answer

The minimum wavelength of an X-ray can be calculated using the equation:

ext{Energy} = rac{hc}{ ext{wavelength}}

For a 50 kV tube, the energy of the X-ray is 50 keV, which can be converted to joules, and we use Planck's constant (h) and the speed of light (c) to find the wavelength.

Step 9

State two design features of an X-ray tube that take account of this.

96%

101 rated

Answer

  1. Tungsten target: The tungsten target is used due to its high atomic number, which increases the efficiency of X-ray production.

  2. Cooling fluid: A cooling fluid is used in the X-ray tube to dissipate the heat generated by the electrons colliding with the target.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;