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What is the Doppler effect? Explain, with the aid of labelled diagrams, how the Doppler effect occurs - Leaving Cert Physics - Question 10 - 2014

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What is the Doppler effect? Explain, with the aid of labelled diagrams, how the Doppler effect occurs. An ambulance siren emits a sound of frequency 750 Hz. When t... show full transcript

Worked Solution & Example Answer:What is the Doppler effect? Explain, with the aid of labelled diagrams, how the Doppler effect occurs - Leaving Cert Physics - Question 10 - 2014

Step 1

What is the Doppler effect?

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Answer

The Doppler effect is the apparent change in the frequency of a wave that occurs due to the relative motion between the source of the wave and the observer. When the source is moving towards the observer, the observed frequency increases. Conversely, when the source is moving away, the observed frequency decreases.

Step 2

Explain, with the aid of labelled diagrams, how the Doppler effect occurs.

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To explain the Doppler effect, we can use labelled diagrams that show concentric circles emanating from a moving source. As the source approaches the observer, the waves are compressed, resulting in higher frequency (shorter wavelength) sound waves being detected. Conversely, as the source moves away, the waves are stretched, leading to a lower frequency (longer wavelength).

The labelled diagrams should depict:

  1. Source moving towards the observer with non-concentric circles (waves).
  2. Source moving away from the observer with spaced-out concentric circles, demonstrating decreased frequency.

Step 3

What is the speed of the ambulance?

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To find the speed of the ambulance, we can use the Doppler formula: f=fv+vovvsf' = f \frac{v + v_o}{v - v_s} where:
f' = observed frequency (820 Hz)
f = source frequency (750 Hz)
v = speed of sound (assumed to be 343 m/s at 20°C in air)
v_o = speed of the observer (0 m/s, as the observer is stationary)
v_s = speed of the source (the ambulance).

Rearranging the formula, we have: vs=v(ff)vov_s = v \left( \frac{f}{f'} \right) - v_o Substituting the values: vs=343(750820)0=31.5m/sv_s = 343 \left( \frac{750}{820} \right) - 0 = 31.5 m/s Therefore, the speed of the ambulance is approximately 29 m/s.

Step 4

State two other practical applications of the Doppler effect.

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Answer

  1. Speed cameras used by law enforcement to measure the speed of vehicles.
  2. Ultrasound scans in medical diagnostics to monitor blood flow and heart conditions.

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