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What is meant by the term resonance? How would resonance be demonstrated in the laboratory? A set of wind chimes, as shown in the diagram, is made from different lengths of hollow metal tubing that are open at both ends - Leaving Cert Physics - Question 7 - 2013

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What is meant by the term resonance? How would resonance be demonstrated in the laboratory? A set of wind chimes, as shown in the diagram, is made from different le... show full transcript

Worked Solution & Example Answer:What is meant by the term resonance? How would resonance be demonstrated in the laboratory? A set of wind chimes, as shown in the diagram, is made from different lengths of hollow metal tubing that are open at both ends - Leaving Cert Physics - Question 7 - 2013

Step 1

What is meant by the term resonance?

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Answer

Resonance refers to the transfer of energy between two systems that have similar natural frequencies. When an external frequency matches a system's natural frequency, the system begins to oscillate more vigorously.

Step 2

How would resonance be demonstrated in the laboratory?

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Answer

To demonstrate resonance, one might use apparatus such as Barton's pendulum, which consists of a column of air and a tuning fork. The procedure can involve setting one pendulum oscillating and bringing a vibrating fork near it to observe the energy transfer.

Step 3

What name is given to this set of frequencies?

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Answer

The identified frequencies 550 Hz, 1100 Hz, and 1651 Hz are known as overtones or harmonics.

Step 4

Draw labelled diagrams to show how the tube produces each of these frequencies.

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Answer

For each frequency:

  • 550 Hz: The tube has an antinode (A) at both ends, with a node (N) at the center.
  • 1100 Hz: The tube has antinodes at both ends, linked correctly to one node in the center.
  • 1651 Hz: The tube has antinodes at both ends, linked correctly to three nodes within the tube.

Step 5

The length of the metal tube is 30 cm. Use any of the above frequencies to calculate a value for the speed of sound in air.

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Answer

Using the formula for the speed of sound in a tube:

v=fimesextwavelengthv = f imes ext{wavelength}

For the fundamental frequency (550 Hz):

  • The length of the tube is 0.60 m (30 cm).
  • Therefore, the speed of sound is: v=550extHzimes0.60extm=330extm/sv = 550 ext{ Hz} imes 0.60 ext{ m} = 330 ext{ m/s}.

Step 6

Calculate the tension in the wire.

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Answer

Using the formula for the tension of a string:

ho} f^2$$ Where: - Length, L = 0.64 m - Mass per unit length, \( \rho = \frac{m}{L} = \frac{0.048}{12} = 0.004 \text{ kg/m} \) - Fundamental frequency, f = 173 Hz Now substituting the values:

\rho = 0.004 ext{ kg/m}
T = \frac{4 \times 0.64 \times (173)^2}{0.004}
T = 196 ext{ N}

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