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Solving Quadratic Equations with a formula Simplified Revision Notes

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Solving Quadratic Equations with a formula

What is the b-b Formula?

The b-b formula, also known as the Quadratic Formula, is a method used to solve any quadratic equation. Unlike factorising, which works only when a quadratic can be easily broken down into simpler factors, the b-b formula works for all quadratic equations.

A quadratic equation looks like this: ax2+bx+c=0ax^2 + bx + c = 0 where:

  • x2x^2 is the squared term.
  • aa, bb, and cc are numbers.
  • xx is the variable we want to solve for. The formula to solve any quadratic equation is: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Steps to Solve a Quadratic Equation Using the b-b Formula

Let's solve a quadratic equation step by step using the b-b formula.


infoNote

Example Problem:

Solve the quadratic equation: 2x28x+6=02x^2 - 8x + 6 = 0

We'll solve this equation using the b-b formula.


Step 1: Identify the Values of aa, bb, and cc

What we do:

Look at the quadratic equation and identify the values of aa, bb, and cc.

In our example:

  • a=2a = 2 (the number in front of x2x^2)
  • b=8b = -8 (the number in front of xx)
  • c=6c = 6 (the constant term) Why we do it:

We need these values to plug them into the b-b formula.


Step 2: Plug the Values into the b-b Formula

What we do:

Substitute the values of aa, bb, and cc into the formula: x=(8)±(8)24(2)(6)2(2)x = \frac{-(-8) \pm \sqrt{(-8)^2 - 4(2)(6)}}{2(2)}

Why we do it:

This step allows us to set up the equation so we can start solving for xx.

Exam Tip: When substituting values into the formula, always use brackets, especially around negative numbers. This helps prevent mistakes, particularly with minus signs. For example, notice how we used (8)(-8) in brackets to avoid any errors.


Step 3: Simplify Inside the Square Root

What we do:

First, calculate what's inside the square root: x=8±64484x = \frac{8 \pm \sqrt{64 - 48}}{4}

Let's break that down:

  • The (8)-(-8) becomes 88.
  • The 6464 comes from (8)2=64(-8)^2 = 64.
  • The 4848 comes from 4(2)(6)=484(2)(6) = 48. So now, we have: x=8±164x = \frac{8 \pm \sqrt{16}}{4}

Step 4: Calculate the Square Root and Simplify Further

What we do:

Now, we find the square root: 16=4\sqrt{16} = 4

So the equation becomes: x=8±44x = \frac{8 \pm 4}{4}


Step 5: Solve for xx

What we do:

Split the equation into two parts to find the two possible solutions for xx:

  1. x=8+44x = \frac{8 + 4}{4} x=124=3x = \frac{12}{4} = 3
  2. x=844x = \frac{8 - 4}{4} x=44=1x = \frac{4}{4} = 1 So, the solutions are: x=3orx=1x = 3 \quad \text{or} \quad x = 1

Why we do it:

Quadratic equations typically have two solutions. This final step gives us the exact values of xx that make the original equation true.


:::


infoNote

Exam Tip

When using the b-b formula, always remember that quadratic equations usually have two solutions. Make sure to solve for both values of xx by using both the plus (+)(+) and minus ()(-) in the formula.


Summary

Here's a quick recap of what we did:

  1. Identify the Values: Find the values of aa,bb, and cc in the quadratic equation.
  2. Plug into the Formula: Substitute these values into the b-b formula, using brackets to avoid mistakes.
  3. Simplify: Calculate what's inside the square root, then find the square root.
  4. Solve for xx: Split the equation and solve for the two possible values of x. x . By following these steps, you can solve any quadratic equation using the b-b formula. Remember, practice is key, and taking your time to understand each step will make this method much easier!

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