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Different Strategies Simplified Revision Notes

Revision notes with simplified explanations to understand Different Strategies quickly and effectively.

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Different Strategies

Overview

When solving problems in counting and probability, selecting the right strategy is crucial for accuracy and efficiency. The Different Strategies note focuses on approaches to systematically organise and calculate outcomes for a variety of counting problems. These strategies include:

Listing Outcomes

  • List all possible outcomes for simple problems.
  • Useful for visualising and verifying possibilities in small sample spaces.
lightbulbExample

Example: Listing all combinations of two coins tossed.

Using the Fundamental Principle of Counting

Multiply the number of choices at each step to find the total number of outcomes.

lightbulbExample

Example: If a menu offers 33 appetisers and 44 main courses, the total combinations are 3×4=123 \times 4 = 12

Factorials (n!n!)

  • Used to count arrangements (permutations) of nn distinct objects.
  • Formula:
n!=n×(n1)××1n! = n \times (n-1) \times \dots \times 1
lightbulbExample

Example: The number of ways to arrange 44 books on a shelf is 4!=244! = 24

Combinations and Permutations

Permutations:

Arrangements where order matters.

Formula:

P(n,r)=n!(nr)!P(n, r) = \frac{n!}{(n-r)!}
lightbulbExample

Example: Arranging 3 out of 5 letters.

Combinations:

Selections where order does not matter.

Formula:

C(n,r)=n!r!(nr)!C(n, r) = \frac{n!}{r!(n-r)!}
lightbulbExample

Example: Choosing 33 toppings out of 55 for a pizza.

Using Venn Diagrams

  • A visual way to represent sets and their intersections.
  • Useful for solving problems involving multiple overlapping groups.

Worked Examples

infoNote

Example 1: Using the Fundamental Principle of Counting

Problem: A wardrobe contains 55 shirts, 33 trousers, and 22 pairs of shoes.

How many outfits can you make?


Solution:

Step 1: Choices:

  • Shirts: 55
  • Trousers: 33
  • Shoes: 22

Step 2: Multiply choices:

Total Outfits=5×3×2=30\text{Total Outfits} = 5 \times 3 \times 2 = 30

Answer: 3030 outfits.


infoNote

Example 2: Choosing a Committee

Problem: A club has 1010 members. How many ways can a 33-person committee be selected?


Solution:

Order does not matter, so use combinations:

C(10,3)=10!3!(103)!=10×9×83×2×1=120C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120

Answer: 120120 ways.


infoNote

Example 3: Arranging Books on a Shelf

Problem: How many ways can 44 books be arranged on a shelf?


Solution:

Order matters, so use permutations:

P(4,4)=4!=4×3×2×1=24P(4, 4) = 4! = 4 \times 3 \times 2 \times 1 = 24

Answer::success[24: :success[24 arrangements].


Summary

  • Key Strategies:
    1. Listing outcomes.
    2. Fundamental Principle of Counting: Multiply choices.
    3. Factorials: Use n!n! for arranging objects.
    4. Combinations (C(n,r)C(n, r)): Selections where order doesn't matter.
    5. Permutations (P(n,r)P(n, r)): Arrangements where order matters.
    6. Venn diagrams: Visualise and solve set problems.
  • These strategies are essential for solving problems in counting and probability systematically.
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